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shepuryov [24]
3 years ago
5

What is the Milgram experiment?

Physics
1 answer:
lora16 [44]3 years ago
6 0
Stanley Milgram, a psychologist at Yale University, conducted anexperiment<span> focusing on the conflict between obedience to authority and personal conscience. He examined justifications for acts of genocide offered by those accused at the World War II Nuremberg War Criminal trials.</span>
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Why does of beam of light ben when it passes into a new medium?
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Answer:

The bending occurs because light travels more slowly in a denser medium.

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3 years ago
Mixture are the same throughout
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4 years ago
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A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie
ale4655 [162]

Explanation:

It is given that,

Area of nickel wire, A=7.4\ cm^2=7.4\times 10^{-4}\ m^2

Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, B_1=0.5\ T

Final magnetic field, B_2=3\ T

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{B_2-B_1}{t}

\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}

\epsilon=1.65\times 10^{-3}\ V

Induced current in the loop of wire is given by :

I=\dfrac{\epsilon}{R}

I=\dfrac{1.65\times 10^{-3}}{2.4}

I=6.87\times 10^{-4}\ A

So, the induced current in the loop of wire over this time is 6.87\times 10^{-4}\ A. Hence, this is the required solution.

7 0
3 years ago
If i hold a glass full of air upside down, and i take it to the bottom of the swimming pool without tipping it, the density (thi
s2008m [1.1K]
The answer to fill in the blank in the question above is "greater than" based on the physic of the air density. The density of air is affected by the temperature and the pressure based on the ideal gas law. A high pressure will make the air becomes denser and the bottom of swimming pool has a higher pressure than the surface<span>.</span>
6 0
3 years ago
An object is dropped on Earth from a height of 15 m. What is the magnitude of the velocity of the object just as it hits the gro
ivolga24 [154]
Here, we know, according to 3rd Equation of Kinematics, 
v² - u² = 2as

Here, u = 0  [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m

Substitute their values, 
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s

In short, Your Answer would be Option D

Hope this helps!
8 0
3 years ago
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