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Leokris [45]
3 years ago
15

Based on this simulation, how would you describe the relationship between potential energy and kinetic energy? Why does this rel

ationship occur?
Physics
1 answer:
Fudgin [204]3 years ago
6 0

Answer:

The total energy of the skater is the sum of his potential energy and kinetic energy. As potential energy decreases, kinetic energy increases, and vice versa. This occurs because kinetic energy is the energy of motion and potential energy is stored energy.

Explanation:

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A stone is dropped down a well and hits the water 2.50 s later. What is the depth from the edge of the well to the water? 61.3,
Gennadij [26K]

Answer;

30.6 m

Explanation;

All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².

Distance traveled by an object falling down under a constant acceleration will be given the formula;

s = ut² + 1/2(gt²); but u the initial velocity is o

thus;

S =1/2(gt²)

  = 0.5 × 9.81 × 2.5 ²

  = 30.65

  ≈ 30.6 m

5 0
3 years ago
A 3,220 lb car enters an S-curve at A with a speed of 60 mi/hr with brakes applied to reduce the speed to 45 mi/hr at a uniform
Grace [21]

The magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

<h3>What is the friction force?</h3>

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. Its unit is Newton (N).

Mathematically, it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

The weight is,W= 3,220 lb

The speed is,u= 60 mi/hr

The reducing speed is,v= 45 mi/hr

The distance traveled is,d= 300 ft

The radius of curvature of the path of the car at B is,R= 600 ft.

1 mile = 5280 ft

From the Newtons' equation of motion;

\rm v^2 = u^2 +2ad \\\\ \rm (45 \times \frac{5280}{3600} )^2 = (60 \times  \frac{5280}{3600}  )^2 +2a\times 300 \\\\

The tangential accelerations are;

\rm a_t = \frac{66^2 -88^2}{600} \\\\ \rm a_t =  -5.65 ft/sec^2 \\\\

The force is found as;

\rm \sum F = ma \\\\ \frac{3220}{32.2} \times -5.65 \\\\ F_T= 565 \ lb

The normal force  is;

\rm F_n = \frac{3220}{32.2} \times \frac{66^2}{600} \\\\ F_N =726 \ lb

The net or the total friction force exerted by the road on the tires at B. is found as;

\rm F = \sqrt{(565)^2+(726)^2} \\\ F = 919.946 \ lb

Hence, the magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

To learn more about the friction force, refer to the link;

brainly.com/question/1714663

#SPJ1

6 0
2 years ago
A man 6 feet tall walks at a rate of 6 feet per second away from a light that is 15 feet above the ground.
Tems11 [23]

Answer:(a)10 ft/s

(b)4 ft/s

Explanation:

Given

height of light =15 feet

height of man=6 feet

\frac{\mathrm{d} x}{\mathrm{d} t}=6 ft/s

From diagram

\frac{15}{y}=\frac{6}{y-x}

5(y-x)=2y

3y=5x

differentiate both sides

3\times \frac{\mathrm{d} y}{\mathrm{d} t}=5\times \frac{\mathrm{d} x}{\mathrm{d} t}

Tip of shadow is moving at the rate of

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{5}{3}\times 6=10 ft/s

(b)rate at which length of his shadow  is changing

Length of shadow is y-x

differentiating w.r.t time

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=\frac{\mathrm{d} y}{\mathrm{d} t}-\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=10-6=4 ft/s

7 0
4 years ago
How would life on earth be different if earth’s axis were not tilted with respect to its orbit?
Vladimir [108]

If Earth's axis was "straight up and down" instead of tilted, then ...

<span>-- There would be no seasons.

-- The climate at any one place would be the same all year around. 

-- The days would be the same length, everywhere,
    and all year around.

-- So would the nights.

-- The sun would be up a little more than 12 hours every day.
    It would be down a little less than 12 hours every day.

-- At the middle of the day, the sun would be at the same height
   in the sky all year around, not higher in some months and lower
   in others.

-- The equator would be the only place on Earth where the sun
    could ever be directly over your head.

-- If you were at the north pole or the south pole, the sun would be
   down on the horizon, and it would just go around and around you
   every day.  It would never rise or set, and it would never get any
   higher or lower.

</span>
4 0
3 years ago
Read 2 more answers
A police officer is using her radar to check speeds. She is moving south at 50 mph. You are moving
Luda [366]

Answer:

the relative speed should be 40mph

Explanation:

8 0
3 years ago
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