Answer:
3.636 hour. dividing 200miles /55m/h =3.636h
Answer:
a.No
b.No
c.No
Step-by-step explanation:
a.No,Such set does not exist .A set of natural numbers is N
Every point of this set is an isolated point but no accumulation point
Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself

Interior point of set :Let
.Then a is called interior point of set when its neighborhood is a subset of set S.

When a set is uncountable then interior point exist it is necessary for interior points existance .
Boundary points :Let
.If every non empty neighborhood of a intersect S and complement of S.
Every member of a set is a boundary point
b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers
c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point
The amount of money he will be able to withdraw after 10 years after his last deposit is $926,400.
<h3>Compound interest</h3>
- Principal, P = $2,000 × 12 × 4
= $96,000
- Time, t = 10 years
- Interest rate, r = 24% = 0.24
- Number of periods, n = 2
A = P(1 + r/n)^nt
= $96,000( 1 + 0.24/2)^(2×10)
= 96,000 (1 + 0.12)^20
= 96,000(1.12)^20
= 96,000(9.65)
= $926,400
Therefore, the amount of money he will be able to withdraw after 10 years after his last deposit is $926,400
Learn more about compound interest:
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Answer:
12600
Step-by-step explanation:
5% of 12000 is 600 so just add them
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab,
is equal to
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus,
. Since a and b were generic elements of H, then H/G is abelian.