1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
3/4+2/3= 17/12
Step-by-step explanation:
Answer:
A. z = 2292.8 is your answer
Step-by-step explanation:
Isolate the variable (z). Note the equal sign, what you do to one side, you do to the other. Add 1092.8 to both sides
z - 1092.8 (+1092.8) = 1200 (+1092.8)
z = 1200 + 1092.8
z = 2292.8
A. z = 2292.8 is your answer
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Answer:
umm its B cause i got it right hope this helped :)
Step-by-step explanation: