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KatRina [158]
2 years ago
10

A box of mass 44 kg is pushed hard enough to set it in motion across a flat surface. The coefficient of kinetic friction between

the box and the surface µk = 0.48. What minimum pushing force is needed to keep the box moving at a constant velocity?
a 231n
b 207n
c 178n
d 283n
Physics
2 answers:
max2010maxim [7]2 years ago
4 0

Answer:

207

Explanation:

For the box to move at a constant velocity, the applied force must cancel the force due to kinetic friction.

F = mu_k * N

N = normal force = weight (= mg) if sliding horizontally

F = mu_k * mg = (0.48)(44 kg)(9.8 m/s^2) = 207 N

VMariaS [17]2 years ago
3 0
Idk tbh I just need to answer
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Taking into account the definition of velocity, Clara's average velocity is 0.5 m/s.

<h3>Definition of velocity</h3>

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction. So it is considered a vector magnitude.

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<h3>Average velocity of Clara</h3>

Clara rushes 30 m to a truck then turns and walks back. Total travel is 120s. Then, you know:

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Current in the coil, i = 1680cos[\frac{\pi t}{0.0250}] A

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We know that maximum emf induced in the coil is given by:

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e = L\frac{d}{dt}(1680)cos[\frac{\pi t}{0.0250}]

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