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Lisa [10]
4 years ago
14

Solve for x in the following expression: 3 / x = 7

Chemistry
2 answers:
amm18124 years ago
4 0
The answer is D) 0.4285
dexar [7]4 years ago
4 0
It would be 21 (B) since to get X by itself, you have to do the opposite sign, which would be be multiplication. so x times 3. and what you do to one side, you do to the other. so 7 times 3= 21.
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Which balanced equation represents an oxidation-reduction reaction?
Bingel [31]

Answer:

Oxidation states are used in chemistry solutions. It is a bond in which electron transfers easily from one nucleus to another nucleus.

Explanation:

  • Oxidation-reduction reactions have some rules.
  • The oxidation state is 0 at an uncombined bond.
  • The bond of oxidation reduction is +1 in alkeli metal.
  • The bond in two metal is +2
  • The oxidation reduction state at helogens is -1. It does not happened always.
  • The oxygen bond in oxidation and reduction is -2.
  • The sum of the oxidation state is equal to the compound charges.
  • In this process the changes occur for any elements. Redox could be occur. Its oxidized and reduction reaction can be seen in this process.
7 0
3 years ago
The atomic mass of sulfur is 32.1 amu, and the atomic mass of oxygen is 16.0 amu. To the nearest tenth of a percent, what is the
Zielflug [23.3K]

Answer:

\%\ Composition\ of\ sulfur=40.1\ \%

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given , Mass of sulfur= 32.1 amu

Mass of oxygen = 16.0 amu

Mass of sulfur trioxide SO_3 = 32.1 amu + 3*16.0 amu = 80.1 amu

\%\ Composition\ of\ sulfur=\frac{Mass_{sulfur}}{Mass_{SO_3}}\times 100

\%\ Composition\ of\ sulfur=\frac{32.1\ amu}{80.1\ amu}\times 100=40.1\ \%

6 0
3 years ago
Gasoline is a mixture of compounds. A gasoline sample was found to be 2.851% (by mass) octane (C₈H₁₈). 482.6 g of gasoline is co
Pani-rosa [81]

Answer:

See below.

Explanation:

The mass of octane in the sample of gasoline is 0.02851 * 482.6 =  13.759 g of octane.

The balanced equation is:

2C8H18(l)  +  25O2(g) ---->  16CO2(g)  +   18H2O(g)

From the equation, using  atomic masses:

228.29 g of  octane forms 704 g of CO2 and 324.3 g of H2O

So the mass of CO2 formed from the combustion of 13.759 g of octane = (704 * 13.759) / 228.29

= 42.43 g of CO2.

Amount of water = 324.3 * 13.759) / 228.29

= 19.55 g of H2O.

5 0
3 years ago
G Calculate the mass, in grams, of 225.0 atoms of cadmium, Cd (1 mol of Cd has a mass of 112.41 g).
serious [3.7K]
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3 0
3 years ago
Vein deposits are usually produced by _____. weathering density sorting hydrothermal solutions cementation
mart [117]

Answer:

Hydrothermal solutions

Explanation:

Vein deposits which cuts through rock layers are usually products of hydrothermal solutions.

Veins are rich ore deposits in which superheated water rich in dissolved minerals penetrated through a rock body and the minerals becomes precipitated and deposited in the process. Most veins have small width and a great length. Some occurs as veinlets depending on the nature of the weaknesses they trace out in a rock body.

Veins contains minerals such as gold, copper ore, rare earth metals. Most hydrothermal solutions contains minerals that are not compatible with the melt as rocks crystallize. They preferred to be carried with super heated water which deposits them seperately.

4 0
3 years ago
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