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Morgarella [4.7K]
3 years ago
15

Why is a shoe considered individual evidence

Chemistry
2 answers:
vlada-n [284]3 years ago
6 0
Because someone was wearing it and their dna could be in it i’m guessing
Arada [10]3 years ago
6 0

Answer:

maybe because someone that could be the suspect might have wore it and its dna or something might have been on it i dunno

Explanation:

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Which is the largest?<br> O 43.32 mL<br> 0 0,0056 L<br> O 0.000076 KL
mel-nik [20]

Answer:

43.32 ML is bigger

3 0
3 years ago
Read 2 more answers
What is the source of energy in nuclear power plants?
Zinaida [17]

Answer:

<h2><em><u>URANIUM</u></em><em><u> </u></em></h2>

Explanation:

What is the source of energy in nuclear power plants?

<em><u>Uranium</u></em> is the fuel most widely used by nuclear plants for nuclear fission. <u>Uranium</u> is considered a nonrenewable energy source, even though it is a common metal found in rocks worldwide. Nuclear power plants use a certain kind of uranium, referred to as U-235, for fuel because its atoms are easily split apart.

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2 years ago
9. Diamonds and quartz crystals look very similar but diamonds cost considerably
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Natural diamonds are made very deep within earth's surface where high temperatures and pressure exist naturally, thus making them much more difficult to obtain, and making them a more expensive option that Swarovski Crystal.
8 0
3 years ago
Hydrogen is a possible future fuel. However, elemental hydrogen is rare, so it must be obtained from a hydrogen- containing comp
dimulka [17.4K]

Answer:

1.1 × 10² g

Explanation:

First, we will convert 1.0 L to cubic centimeters.

1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³

The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:

1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:

1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

4 0
3 years ago
30 its ASAP!!!! What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?
USPshnik [31]
Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 &deg; C = 23+273.15 = 296.15 &deg; K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = <span>0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)

</span>
5 0
3 years ago
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