Answer: amount = 2466.95L
Explanation:
given that the speed is = 1900./kmh i.e. 1hr/900km
distance = 1050km
the fuel burns at a rate of 74.4 L/min
therefore the amount of fuel that the jet consumes on a 1050.km becomes;
total fuel used = time × fuel burning rate
where time = distance / speed
∴ total fuel used (consumed) = time × fuel burning rate
total fuel consumed = (1050km × 1hr/1900km) × (60min/ 1hr × 74.4L/1min)
total fuel consumed = 2466.95L
Nitrogen is present in excess.
<h3>What is the no. of moles of nitrogen?</h3>
3Mg + N2 = Mg3N2
Moles of Mg = mass / molar mass = 2.22 / 24.3 = 0.0914
Moles of N2 = 3.75 / 28=0.1339
In conclusion, as we produce less amount of M g3N 2 when we assumed that M g was the limiting reagent, magnesium is the limiting reagent and nitrogen is the excess.
<h3>How can magnesium nitride be made through a direct reaction?</h3>
The elements can directly react to form magnesium nitride, as demonstrated in the equation 3 mg (s)+n2 (g)=Mg3N2 (s).
<h3>What is excess reactant?</h3>
Reactants that are not totally consumed are referred to as "excess reactants," whereas reactants that are completely consumed or reacted are referred to as "limited reactants." How much of the limiting reactants are consumed determines how much product is generated. In this section, the definition of excess reactant, examples, and calculations are discussed.
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C = 1.14 M , T = 10 + 273.15 = 283.15 K salt concentration = 176 mg /L NaCl
π total = CRT = 1.14 x 0.0821 x 283.15 = 26.5 atm
mass of NaCl = 176 mg = 0.176 g
Molarity =
![\frac{0.176}{57.96} x \frac{1}{1L} = 3.0366 x 10^{-3} M](https://tex.z-dn.net/?f=%20%5Cfrac%7B0.176%7D%7B57.96%7D%20x%20%20%5Cfrac%7B1%7D%7B1L%7D%20%20%3D%203.0366%20x%2010%5E%7B-3%7D%20M%20%20)
maximum concentration allowed C = 3.0366 x 10⁻³ M
π max. conc. = 2 x 3.0366 x 10⁻³ x 0.0821 x 283.15 = 0.141 atm
π external = π total - π max. conc.
= 26.5 - 0.141 = 26.3 atm
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Answer:
A sample of salt has 1.74 moles of sodium chloride. how many formula units of the ionic compound are in the sample?
Explanation:
Given, 1.74 moles of NaCl.
Since one mole of NaCl consists of ---
formula units.
Then, 1.74mol of NaCl contains how many formula units of NaCl?
formula units.
Hence, the given sample has 10.5x10^23 formula units.