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fomenos
3 years ago
8

A locomotive is pulling 8 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (wi

th its load) is 37,000 kg. If the train is accelerating at 0.48 m/s2 on a level track, what is the tension in the coupling between the second and third cars? (The car nearest the locomotive is counted as the first car, and friction is negligible.)
Physics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:106560 N

Explanation:

Given

Let Tension between  2 and 3 car be T_{23} and between 3 &4 is T_{34}

T_{23}-T_{34}=ma

mass of freight car =37,000 kg

acceleration of car=0.48 m/s^2

T_{34} is accelerating all freights behind 3

therefore

T_{34}=5\times ma

T_{34}=5\times 37000\times 0.48=88,800 N

Thus

T_{23}=T_{34}+ma

T_{23}=88,800+37000\times 0.48=88,800+17,760=106560 N

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Charged beads are placed at the corners of a square in the various configurations shown in
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A cross-country skier moves 36 meters eastward, then 44
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Answer:

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Let the east ward be positive and the west ward be negative.

Since the skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward. Then, that will be:

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Answer:

a.1017.9N

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h1=height

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1.0179*10^5Pa

at the level of the bottom of the block we have

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(c)  Archimedes principle state that, the buoyant force on the block equals the weight of the displaced water. Thus,

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= = 1000* 0.100^2 * 0.120 m *9.80 m s=11.8 N

from the answer a Ftop-Fbot

1029.7-1017.9=11.8N, the same as the buoyant force

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3 years ago
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