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ivanzaharov [21]
3 years ago
10

Find the mean and the standard deviation for each set of values. Show your work. 15,17,19,20,14,23,12

Mathematics
1 answer:
vekshin13 years ago
3 0
1. Mean.

\overline{x}=\dfrac{15+17+19+20+14+23+12}{7}=\dfrac{120}{7}\approx\boxed{17.14}

2. <span>Standard deviation.

First we have to square each value and calculate the mean of that squares:

\overline{x^2}=\dfrac{15^2+17^2+19^2+20^2+14^2+23^2+12^2}{7}=\boxed{\dfrac{2144}{7}}

so the variance:

s^2=\overline{x^2}-\overline{x}^2=\dfrac{2144}{7}-\left(\dfrac{120}{7}\right)^2\approx\boxed{12.41}

and the standard deviation:

s=\sqrt{s^2}=\sqrt{12.41}\approx\boxed{3.52}
</span>
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Please help me on 7&amp;8 and please show your work :)
Llana [10]
7. 6/12 or 1/2 | 8. 5/12

5 0
3 years ago
Please help.. no links​
neonofarm [45]

Answer:

Its 9.0 units

Step-by-step explanation:

For the side mostly to the left, its gonna be 3 units, since we can easlily count it

Now, for the diagonals, we have to use the formula for the area of a triangle, which is (l * w) / 2 = a.

For the bottom side, its 3 along the x axis and 1 along the y axis. 3 * 1 is 3, now divide that by 2 and you got 1.5

Now, for the right side, its 5 on the y, 1 on the x. Multiply 1 by 5, you got 5. Now divide that by 2 and you have 2.5

Finally, for the top side, its 4 on the x, and 1 on the y. 4 * 1 is 4, divided by 2 and its 2.

Alright, now we have to add 'em all together. 3 + 1.5 + 2.5 + 2 is 9 units

Theres your answer :)

6 0
2 years ago
Based on the triangle given, determine the trig ratio of the cos 0
likoan [24]

Answer:

cos theta = 4/5

Step-by-step explanation:

Since this is a right triangle

Cos theta = opp side/ hypotenuse

Cos theta = 8/10

cos theta = 4/5

4 0
3 years ago
I'M OFFERING 20 POINTS-
Dafna11 [192]

Answer:

Third option is correct. Scale factor 3 ; enlargement.

Step-by-step explanation:

It is given that the figure A'B'C'D' is a dilation of figure ABCD.

We know that after dilation the corresponding sides of image and preimage are in the same proportion.

The image of AD is A'D'.

From the figure it is noticed that the A(-1,2), D(-1,-1), A'(-3,6) and D'(-3,-3).

Distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AD=\sqrt{(-1+1)^2+(-1-2)^2}=\sqrt{9}=3

A'D'=\sqrt{(-3+3)^2+(-3-6)^2}=\sqrt{81}=9

Scale factor is constant which represents the relation between image and preimage.

k=\frac{A'D'}{AD}

k=\frac{9}{3}

k=3

Therefore the scale factor is 3.

If k>0 it means enlargement and if k<0 it means reduction. Therefore third option is correct.

3 0
3 years ago
Read 2 more answers
40% of 125 is what number?
Hatshy [7]
The answer is 32


Solution for 40 is what percent of 125:

40:125*100 =

( 40*100):125 =

4000:125 = 32

Now we have: 40 is what percent of 125 = 32

Question: 40 is what percent of 125?

Percentage solution with steps:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=125$100%=125​.

Step 4: In the same vein, $x\%=40$x%=40​.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$100%=125(1)​.

$x\%=40(2)$x%=40(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{125}{40}$
100%
x%​=
125
40​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{40}{125}$
x%
100%​=
40
125​​

$\Rightarrow x=32\%$⇒x=32%​

Therefore, $40$40​ is $32\%$32%​ of $125$125​.
7 0
3 years ago
Read 2 more answers
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