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Artemon [7]
3 years ago
5

Can you get molecules to stop wiggling??

Chemistry
1 answer:
lilavasa [31]3 years ago
5 0
No, molecules don’t ever stop moving
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What is the molarity of a solution prepared by diluting 43.72 ml of 1.005 M aqueous K2CR2O7 to 500 ml
UNO [17]

Answer:

43.72

Explanation:

that is the answer hope u liked it and I did this already along time ago

3 0
3 years ago
Write the symbol for every chemical element that has atomic number less than 75 and atomic mass greater than 173.5 u.
bearhunter [10]
Following are the chemical elements that have atomic mass greater than 173.5 u and atomic number less than 75.

1.  Lutetium
                  Atomic Number  =  71
                  Atomic Mass      =  174.97 u

2.  Hafnium
                  Atomic Number  =  72
                  Atomic Mass      =  178.49 u

3.  Tantalum
                  Atomic Number  =  73
                  Atomic Mass      =  180.95 u

4.  Tungsten
                  Atomic Number  =  74
                  Atomic Mass      =  183.85 u
8 0
3 years ago
1. A doctor has ordered 1.5 liters of normal saline for a patient. If it has to be given over 10 hours, how many liters per hour
max2010maxim [7]
.15 liters of normal saline will drip into the patient's IV per hour.
7 0
3 years ago
Why is the C-14/C-12 ratio used to date once-living organisms?
vredina [299]
D. An organism stops taking in carbon when it dies.
6 0
3 years ago
Ydrogen and fluorine combine according to the equation h2(g) + f2(g) → 2 hf(g) if 5.00 g of hydrogen gas are combined with 38.0
Alexxx [7]
<span> Molar mass (H2)=2*1.0=2.0 g/mol
Molar mass (F2)=2*19.0=38.0 g/mol
Molar mass (HF)=1.0+19.0=20.0 g/mol

5.00 g H2 * 1mol H2 /2 g H2=2.50 mol H2 
38.0 g F2*1mol F2/38.0 g F2=1.00 mol F2

                                   H2(g) + F2(g) → 2 HF(g)
From reaction        1 mol      1 mol
From problem      2.50 mol   1 .00mol

We can see that  excess of H2, and that F2 is a limiting reactant.
So, the amount of HF is limited by the amount of F2.

</span>                                 H2(g) + F2(g) → 2 HF(g)
From reaction                      1 mol       2  mol
From problem                      1.00 mol  2.00mol

2.00 mol HF can be formed.

2.00 mol HF*20.0g HF/1mol HF=40.0 g HF can be formed
4 0
3 years ago
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