M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,
Q = mc(θ₂ - θ₁)
Q = 0.004*0.440*(21 - 0)
Q = 0.03696 kJ
0.03696 kJ<span> of heat is absorbed.</span>
For the 1st order reactions,rate constant (k) is mathematically expressed as
k =

where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'
Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s
Therefore, we have
</span>2.20 × 10^-5 =

∴

= 0.06877
∴,

= 1.1716
∴, Ct = 85.35%
Thus, <span>
85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
Answer:
Explanation:
As you move down a group, first ionization energy decreases. WHY? Electrons are further from the nucleus and thus easier to remove the outermost one.
The reactant in aerobic respiration is oxygen (answer C)
Answer:
W = -262 J.
Explanation:
Hello there!
In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

So we plug in the given pressure and volumes to obtain:

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

Regards!