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Artemon [7]
3 years ago
5

Can you get molecules to stop wiggling??

Chemistry
1 answer:
lilavasa [31]3 years ago
5 0
No, molecules don’t ever stop moving
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A 4.000 g sample of iron was heated from 0.0°C to 21.0°C. If it has a specific heat of 0.440 kJ/kg °C, how many kilojoules of he
Mashutka [201]
M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,

Q = mc(θ₂ - θ₁)

Q = 0.004*0.440*(21 - 0)

Q  =  0.03696 kJ 

0.03696 kJ<span> of heat is absorbed.</span>
6 0
3 years ago
The first-order reaction, so2cl2 → so2 + cl2, has a rate constant equal to 2.20 × 10-5 s-1 at 593 k. what percentage of the init
Svetradugi [14.3K]
For the 1st order reactions,rate constant (k) is mathematically expressed as

k = \frac{2.303}{t}log \frac{Co}{Ct}
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'

Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s

Therefore, we have
</span>2.20 × 10^-5 = \frac{2.303}{7200}log \frac{100}{Ct}
∴ log\frac{100}{Ct} = 0.06877
∴, \frac{100}{Ct} = 1.1716
∴, Ct = 85.35%

Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
4 0
3 years ago
Lonization Energy decreases as you go down a family (group or column). Explain why this pattern
Goryan [66]

Answer:

Explanation:

As you move down a group, first ionization energy decreases. WHY? Electrons are further from the nucleus and thus easier to remove the outermost one.

3 0
2 years ago
Which of the following is a reactant in aerobic respiration?
IrinaVladis [17]
The reactant in aerobic respiration is oxygen (answer C)
3 0
2 years ago
How much work (in J) is involved in a chemical reaction if the volume decreases from 4.35 to 1.20 L against a constant pressure
Marianna [84]

Answer:

W = -262 J.

Explanation:

Hello there!

In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:

W=P(V_2-V_1)

So we plug in the given pressure and volumes to obtain:

W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L

Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:

W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J

Regards!

3 0
3 years ago
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