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Svetach [21]
2 years ago
5

Using the graph below please draw a reaction potential energy diagram for a reaction with the

Chemistry
1 answer:
azamat2 years ago
7 0

Answer:

12

Explanation:

because it is the sam

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But-1-ene can be prepared from butan-1-ol. which type of reaction takes place?
slega [8]

Answer:

              Dehydration Reaction

Explanation:

                  Alcohols can be converted into Alkenes using catalytic amounts of acids as a catalysts.

                 The water molecule is removed hence, it is called as dehydration reaction.

                  The reaction is attached.

8 0
2 years ago
Which best describe the tyndall effect
Svet_ta [14]

The answer would be A

6 0
3 years ago
How many moles of dipyrithione contain 8.2 x 10^24 atoms of N
Pani-rosa [81]
Dipyrithione is a chemical with formula, C₁₀H₈N₂O₂S₂. This means that each molecule of the substance has two (2) atoms of nitrogen. By using the dimensional analysis and Avogadro's number, equal to 6.022 x 10²³, we calculate for the answer as shown below.

    n = (8.2 x 10²⁴ atoms N)(1 molecule dipyrithione/ 2 atoms of N)(1 mole dipyrithione/ 6.022 x 10²³ molecules dipyrithione)

Simplifying,
  n = 6.8 moles dipyrithione

<em>ANSWER: 6.8 moles</em>
4 0
3 years ago
A light or optical microscope most commonly uused is a
kirill115 [55]
A bright feild is most commonly used 
4 0
3 years ago
How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
2 years ago
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