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4 years ago

The two esters below are synthesized from the starting material below. identify and draw the neutral reagent that is missing.

Chemistry

1 answer:

schepotkina [342]4 years ago

4 0

The two Esters along with starting materials are shown below. The missing reagents ate shown in Blue encircled in red box. First reaction is carried out in acid which increases the reactivity of carboxylic acid (electrophilicity odf carbonyl carbon). And second reaction is carried out in the presence of Base, which increases the Nucleophilicity of nucleophile i.e. Alcohols.

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Question 3(Multiple Choice Worth 3 points)

vovikov84 [41]

Answer:

kilograms

Explanation:

5 0

3 years ago

At equilibrium, a 1.0 L reaction vessel contains 2.3 mol of Mg(OH)₂ and 0.170 mol of OH⁻. What is the equilibrium concentration

Andru [333]

The value of X for this chemical reaction is 1.65 x 10⁻⁴

Explanation:

Mg (OH)₂(s) <==> Mg²⁺+(aq) + 2OH₋₁(aq)

Kc= 1.80x10⁻¹¹

KC = [Mg²⁺][OH-]²

Let us assume

Put X = [Mg²⁺] and 2x = [OH-]

1.80x10-11 = (X) (2X)²

1.80x10-11 = 4X³

X³ = 4.5x10⁻¹²

On simplifying the equation we get,

X = 1.65 x 10⁻⁴

The value of X for this chemical reaction is 1.65 x 10⁻⁴

7 0

3 years ago

g You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each

RUDIKE [14]

Answer:

For a: Lead iodide is a yellow precipitate.

For b: Barium sulfate is a white precipitate.

For c: Ferric hydroxide is a brown precipitate.

For d: Copper (II) hydroxide is a blue precipitate.

Explanation:

Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.

For the given options:

For (a):

The chemical reaction between KI and lead (II) nitrate follows:

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.

For b:

The chemical reaction between barium chloride and sulfuric acid follows:

$BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)$

The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.

For c:

The chemical reaction between NaOH and ferric chloride follows:

$3NaOH(aq)+FeCl_3(aq)\rightarrow Fe(OH)_3(s)+3NaCl(aq)$

The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.

For d:

The chemical reaction between NaOH and copper sulfate follows:

$CuSO_4+2NaOH\rightarrow Cu(OH)_2+Na_2SO_4$

The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.

6 0

3 years ago

Is lithium (Li) more or less reactive than beryllium (Be)? Why?

balu736 [363]

Answer:

Lithium is more reactive as it has only one electron in its valance shell. Beryllium has 2 valance electrons. Lithium is more reactive as it is easier to lose oneelectron than losing two electrons.

3 0

3 years ago

Read 2 more answers

Write the charge balance for a MgSO 4 and NaNO 3 solution that contains H + , OH − , Mg 2 + , HSO − 4 , SO 2 − 4 , MgHSO + 4 , M

irga5000 [103]

Answer :

$MgSO_4$ solution contains $Mg^{2+}$ and $SO_4^{2-}$