1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allushta [10]
3 years ago
8

Are Li, Na and K in the same group

Chemistry
1 answer:
Stells [14]3 years ago
7 0

Answer: Yes, they are.

Explanation:

Yes, they are. Li, Na, and K are referring to  Lithium, sodium, and potassium.

They are all belonging to the same group which is called the alkali metals group.

They are having the same number of valence electrons i.e. 1.

This group of the alkali metals are considering tree more metals in it which are Rb, Cs, and Fr.

You might be interested in
For the reaction A(g)
zubka84 [21]

Answer:

Yes

Explanation:

By definition, the equilibrium constanct, Kc, for the reaction A ⇒ 2B is

= [A]^1 / [B]^2

Substitute [A] = 4 and [B] = 2 in the equation,

[A]^1 / [B]^2

= 4^1 / 2^2

= 1

= Kc

So yes the reaction is at equilibrium.

6 0
2 years ago
Studying energy involves determining the amount of energy an object has. This energy can be kinetic or potential, or it could be
Flura [38]

Answer: the answer is a

Explanation:

3 0
3 years ago
BRAINLIESTTT ASAP!!!! PLEASE HELP ME :)
Elan Coil [88]

Answer:

1s² 2s²2p³  

Explanation:

If the atom has seven electrons, it is Element 7 (nitrogen).

In the Periodic Table, you count the electrons in all the subshells up to

No. 7.

In the first Period, you have filled the 1s level (2 electrons).

In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.

Thus, the electron configuration is

1s² 2s²2p³

Note how the superscripts tell you the number of electrons in each subshell: <em>2 + 2 + 3 = 7</em>.

6 0
3 years ago
3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
2 years ago
Which particles give the nucleus its posyive charge
Slav-nsk [51]
Proton gives nucleus positive charge P+
6 0
3 years ago
Read 2 more answers
Other questions:
  • Given the chemical formulas Na2O, MgO, and Al2O3, predict the formula for radioactive francium oxide, Fr?O?.
    10·2 answers
  • How many significant digits are there in the measurement of 9478.983560 cm
    6·1 answer
  • How many deciliter a of a .88M Lif solution be made using 25.5 cg Lif? Lif molar mass = 25.94 g/mol
    12·1 answer
  • Put 2.35x104 in standard notation.
    12·1 answer
  • 8. An atom has 9 protons, which element is it?​
    14·2 answers
  • What is this please helppp​
    7·1 answer
  • Can someone help me please
    14·1 answer
  • What is neutralisation-acid and base?
    12·1 answer
  • Describe are seasons like near the equator.
    9·1 answer
  • This table lists some characteristics of two planets.<br> Which statement is true?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!