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3 years ago

Which of the following statements about protons are true?

Chemistry

2 answers:

Mashutka [201]3 years ago

8 0

Protons have the same magnitude of charge as electrons but are opposite in sign.

attashe74 [19]3 years ago

4 0

The second on it true

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It indicates that the ratio of the particles in the composition of the sample will always be 2:1 with Hydrogen: Sulfur

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A chemist wishes to prepare a pure sample of silver bromide (agbr). first the chemist combines hydrobromic acid (hbr) and silver

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You need to boil away the water from the solution next.

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4 years ago

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What is the atomic number for an element with 6 neutrons and a mass number of 10

Whitepunk [10]

$\bold{\huge{\blue{\underline{Answer}}}}$

$\bold{\underline{ Given :- }}$

Atomic number of an element with 6 neutrons and a mass number of 10

$\bold{\underline{ Let's \:Begin}}$

$\sf{We\: know\: that, }$

Atomic number is the number of protons in the nucleus of an atom

$\sf{Whereas ,}$

Mass number is the sum of protons and neutrons in the nucleus of an atom.

$\sf{We\: have \:number \:of \:neutrons = 6 }$

$\sf{ Mass\: number = 10 }$

$\bold{\underline{Therefore}}$

$\sf{ Mass\: number = Protons + neutrons}$

$\sf{ 10 = Protons + 6 }$

$\sf{ Protons = 10 - 6}$

$\sf{ Protons = 4 }$

$\sf{ Thus, \: the \: number \: of \: protons \: is \:4}$

$\bold{\underline{ Therefore,\:we\:know\:that, }}$

$\sf{ No\: of\: protons = Atomic \:number }$

$\sf{ 4 = Atomic \:number }$

$\sf { Hence, \:atomic\: number\: of\: the\: element\: is\: 4}$

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2 years ago

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An electric field travels away from a charge and toward a _?_ charge.

andre [41]

An electric field travels away from a <u>positive charge</u> and toward a <u>negative charge</u>.

<h3>What is electric field?</h3>

Electric field is the region of space where the impact of electric force is felt.

The electrostatic field is always directed away from positive charges and toward negative charges, and, field lines must go away from positive charges and toward negative ones.

Thus, an electric field travels away from a positive charge and toward a negative charge.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

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2 years ago

For chemical reactions involving ideal gases, the equilibrium constant K can be expressed either in terms of the concentrations

miskamm [114]

Answer:

$K_p= 3966.01$

Explanation:

The relation between Kp and Kc is given below:

$K_p= K_c\times (RT)^{\Delta n}$

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

$2CH_4_{(g)}\rightleftharpoons C_2H_2_{(g)}+3H_2_{(g)}$

Given: Kc = 0.140

Temperature = 1778 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (1778 + 273.15) K = 2051.15 K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (3+1)-(2) = 2

Thus, Kp is:

$K_p= 0.140\times (0.082057\times 2051.15)^{2}$

$K_p= 3966.01$

6 0

3 years ago