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vlabodo [156]
3 years ago
5

Which of the following statements is FALSE? A. Air temperatures over the ocean remain fairly constant throughout a 24-hour cycle

. B. Air temperatures over the land can vary significantly throughout the day. C. Air temperatures over land reach their highest values in the mid-afternoon. D. Air temperatures over land are always higher than air temperatures over the ocean.
Chemistry
2 answers:
e-lub [12.9K]3 years ago
7 0

Answer:

d

Explanation:

kozerog [31]3 years ago
3 0

Answer:

The answer is D

Explanation:

i just took the lab on edge

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How many HCL-molecules in 1,5mol HCL
Vera_Pavlovna [14]

Answer:

number of molecules =9.03×10^23

Explanation:

use the equation

n=number of molecules /Av.constant

make number of Molecules become the subject of the formula by multplying Av.constant on both sides of the equation,

number of molecules=n×Av. constant ,where Av.constant is 6.02×10^23

number of molecules=1.5mol×6.02×10^23

=9.03×10^23

3 0
3 years ago
A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal
bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}

\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}

Solving for V₂ , we get:

<u>V₂ = 45.0 L</u>

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0
4 years ago
In 1 kilogram of pure water, the mass of hy drogen atoms is approximately 112 grams, or 0.112 kilograms. what is the energy equi
zlopas [31]
1.008x10^16 Joules. Technically a theory and not a law. but E=MC^2!
energy=mass ×speed of light squared.
J=kg×(m/s)^2
3 0
4 years ago
A balanced equation for the dissociation of KI
Ann [662]

Answer:

The balanced equation for the dissociation of KI is

KI →  K⁺ + I⁻

Explanation:

KI is the potassium iodide.

K⁺ comes from the KOH, a strong base, so the cation is the conjugate weak acid and in water it does not react.

I⁻ comes from HI, a strong acid, so the anion is the conjugate weak base and in water it does not react.

K⁻  + H₂O ← KOH + H⁺

I⁻ + H₂O ← HI + OH⁻

That's why the arrow in the reaction is in the opposite direction.

3 0
3 years ago
Enter a chemical equation for HI(aq) showing how it is an acid or a base according to the Arrhenius definition. Consider that st
jek_recluse [69]

Answer:

HI (aq) → H⁺ (aq) +  I⁻ (aq)

HI (aq) +  H₂O(l)  → H₃O⁺ (aq) +  I⁻ (aq)

Explanation:

The Arrhenius acid concept indicates that a substance behaves like acid if it produces hydrogen ions H⁺ or hydronium ions H₃O⁺ in water. A substance will be classified as a base if it produces OH⁻  hydroxide ions in water. This way of defining acids and bases works well for aqueous solutions.

When we mix HI (aq) and water, we are increasing [H₃O⁺]

HI (aq) → H⁺ (aq) +  I⁻ (aq)

HI (aq) +  H₂O(l)  → H₃O⁺ (aq) +  I⁻ (aq)

7 0
4 years ago
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