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ad-work [718]
3 years ago
7

What is the molar mass of 3.45 moles of NO2

Chemistry
2 answers:
marissa [1.9K]3 years ago
4 0

I Believe it would be 46.005500

hoped this helped let me know if I'm wrong

Vinil7 [7]3 years ago
4 0

<u>Answer:</u> The mass of nitrogen dioxide for given number of moles are 158.7 grams.

<u>Explanation:</u>

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Moles of nitrogen dioxide = 3.45 moles

Molar mass of nitrogen dioxide = [14+(2\times 16)]=46g/mol

Putting values in above equation, we get:

3.45mol=\frac{\text{Mass of }NO_2}{46g/mol}\\\\\text{Mass of }NO_2=(3.45mol\times 46g/mol)=158.7g

Hence, the mass of nitrogen dioxide for given number of moles are 158.7 grams.

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Answer:

1) 6.0 atm.

2) 2.066 atm.

Explanation:

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<em>PV = nRT.</em>

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V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

<em>1) What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperature is held constant?</em>

  • At constant T and at two different (P, and V):

<em>P₁V₁ = P₂V₂.</em>

P₁ = 2.0 atm, V₁ = 150.0 mL.

P₂ = ??? atm, V₂ = 50.0 mL.

<em>∴ P₂ = P₁V₁/V₂</em> = (2.0 atm)(150.0 mL)/(50.0 mL) = <em>6.0 atm.</em>

<em>2. A sample of a gas in a rigid container at 30.0°C and 2.00 atm has its temperature increased to 40.0°C. What will be the new pressure?</em>

<em></em>

  • Since the container is rigid, so it has constant V.
  • At constant V and at two different (P, and T):

<em>P₁/T₁ = P₂/T₂.</em>

P₁ = 2.0 atm, T₁ = 30.0°C + 273 = 303 K.

P₂ = ??? atm, T₂ = 40.0°C + 273 = 313 K.

<em>∴ P₂ = P₁T₂/T₁ </em>= (2.0 atm)(313.0 K)/(303.0 K) =<em> 2.066 atm.</em>

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