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GuDViN [60]
3 years ago
9

Bud N. Chemist must determine the density of a mineral sample. His four trials yield densities of 4.77 g/cm3 , 4.67 g/cm3 , 4.69

g/cm3 , and 4.81 g/cm3 . Independent studies found the correct density to be 4.75 g/cm3 . Which of the following statements represents the best analysis of the data? A) Bud's results have much greater accuracy than precison B) Bud's results have much greater precision than accuracy C) Bud's results have high accuracy and high precision D) Bud's results have low accuracy and low precision E) Bud's equipment is faulty
Chemistry
1 answer:
Sati [7]3 years ago
7 0

Answer:

A

Explanation:

PRECISION AND ACCURACY ARE TERMS THAT ARE USED TO INDICATE THE QUALITY OF A GIVEN SET OF STATISTICAL OBSERVATIONS.

WHILE PRECISION TALKS ABOUT THE LEVEL OF AGREEMENT AMONGST THE SAME SET OF DATA OBSERVATIONS, ACCURACY TALKS ABOUT HOW FAR OR HOW CLOSE THE TRUE VALUE IS TO THE CALCULATED VALUE. TAKING AN AVERAGE OF ALL THE VALUES, IT STANDS AT 4.735 WHICH IS QUITE CLOSE TO THE TRUE VALUE OF 4.75

NOW, LOOKING AT THE SPREAD OF THE VALUES IN THE OBSERVATION, WE CAN SEE THAT THESE VALUES ARE QUITE NOT CLOSE TO EACH OTHER. HENCE, WE CAN CONCLUDE THAT ALTHOUGH HIS OBSERVATIONS ARE QUITE QUITE ACCURATE BASED ON THE OVERALL AVERAGE, WE CAN CONFIDENTLY POSIT THAT HIS VALUES HAVE A LOW LEVEL OF PRECISION

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A gas has a volume of 5.0 L at a pressure of 50 KPa. What happens to the volume when the pressure is increased to 125?
Alexeev081 [22]
The volume becomes two. You have to use the equation P1 x V1 = P2 x V2 
P is pressure and V is volume.
P1 = 50     P2 = 125
V1 = 5       V2 = v (we don't know what it is)
Then set up the equation:
50 times 5 = 125 times v
250 = 125v
the divide both sides by 125 and isolate v
2 = v
Therefore the volume is decreased to 2.
Also, Boyle's Law explains this too: Volume and pressure are inversely related, This means that when one goes up the other goes down (ie when pressure increases volume decreases and vice versa). Becuase the pressure went up from 50 KPa tp 125 KPa the volume had to decrease.

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Montano1993 [528]

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eight

Explanation:

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2 years ago
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3 years ago
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coldgirl [10]

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3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
katovenus [111]

The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

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<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

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3 years ago
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