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Sidana [21]
3 years ago
11

Find the zeros of f(x) = -x^2 + 4x - 3 by using a table and a graph.

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0
1) <span>Enter the missing numeral of the answer 1, 3. Use a number only.
2) </span>f(x) = x^2 - 5x - 6 can be written as <span>f(x) = x^2 - 5x - 6 = (x-1) (x+6)
the zeros are 1 and 6, and the smallest zero is 1,
3) </span>g(x) = x^2 - 8x =<span>g(x) = x(x - 8), so the zeros are 0 and 8, the smallest zero is 0
4) </span>f(x) = x^2 - 7x + 6 can be written as <span>f(x) = x^2 - 7x + 6 = (x-1) (x-6), the zeros are 1 and -6, and the smallest zero is 1
5) </span>g(x) = x^2- 6x - 16 can be written as <span>g(x) = x^2- 6x - 16 = (x+2) (x-8)
the zeros are -2 and 8, the smallest zero is -2</span>
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16n+8=4
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3 years ago
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Find the length of arc RQ. Use 3.14
Helen [10]

Answer:

The length of arc PQ is 8.1 inches.

Step-by-step explanation:

First, you have to find the angle of POQ. Given that total angles in a circle is 360°, so you have to subtract to get ∠POQ :

73 + 150 + 65 + ∠POQ = 360

288 + ∠POQ = 360

∠POQ = 360 - 288 = 72

Next, you have to apply length of arc formula, Arc = θ/360×2×π×r where θ represents the angle of arc and r is the radius of circle :

arc =  \frac{θ}{360}  \times 2 \times \pi \times r

let \: θ = 72,\pi = 3.14,r = 6.48

arc =  \frac{72}{360}  \times 2 \times 3.14 \times 6.48

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7 0
3 years ago
15 minus the product of 5 times the difference of p minus 6
m_a_m_a [10]
Written just as an expression it would be:

15-5(p-6)
3 0
3 years ago
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the combined area of two squares is 45 square cm. Each side of one square is twice as long as the side of the other Square. What
Vlad1618 [11]

Answer:

L=6 cm l=3

Step-by-step explanation:

x+y=45


L=2l


Big Square Area


L*L=x


Little Square

l*l=y



Substituting

(L*L)+(l*l)=45

(2l*2l)+(l*l)=45

(4l^2)+(l^2)=45

5l^2=45

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l^2=9

l=sqrt(9)

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4 0
2 years ago
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tresset_1 [31]

Answer:

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Step-by-step explanation:

When multiplying exponents(if positive), you must add them together. So, (5q^4)³ will be 5q^7 because the exponents were positive and they were multiplying so you add them together and leave the variable and number 5 alone.

Hope this helps! :)

4 0
3 years ago
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