Answer:
a.) I = 7.8 × 10^-4 A
b.) V(20) = 9.3 × 10^-43 V
Explanation:
Given that the
R1 = 20 kΩ,
R2 = 12 kΩ,
C = 10 µ F, and
ε = 25 V.
R1 and R2 are in series with each other.
Let us first find the equivalent resistance R
R = R1 + R2
R = 20 + 12 = 32 kΩ
At t = 0, V = 25v
From ohms law, V = IR
Make current I the subject of formula
I = V/R
I = 25/32 × 10^3
I = 7.8 × 10^-4 A
b.) The voltage across R1 after a long time can be achieved by using the formula
V(t) = Voe^- (t/RC)
V(t) = 25e^- t/20000 × 10×10^-6
V(t) = 25e^- t/0.2
After a very long time. Let assume t = 20s. Then
V(20) = 25e^- 20/0.2
V(20) = 25e^-100
V(20) = 25 × 3.72 × 10^-44
V(20) = 9.3 × 10^-43 V
Answer:
Cc= 12.7 lb.sec/ft
Explanation:
Given that
m = 22 lb
g= 32 ft/s²
x= 4.5 in
1 in = 0.083 ft
x= 0.375 ft
Spring constant ,K
K= 58.66 lb/ft
The damper coefficient for critically damped system
Cc= 12.7 lb.sec/ft
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Data structures come in both simple and complex forms, all of which are made to organize data for a certain use. Users find it simple to access the data they need and use it appropriately thanks to data structures. The organizing of information is framed by data structures in a way that both machines and people can better grasp. A data structure may be chosen or created in computer science and computer programming to store data in order to be used with different methods. In some circumstances, the design of the data structure and the algorithm's fundamental operations are closely related. Each data structure comprises information about the data values, relationships between the data and — in some situations — functions that can be applied to the data. For instance, in an object-oriented programming language, the data structure and its related methods are tied together as part of a class description. Although they may be designed to operate with the data structure in non-object oriented languages, these functions are not considered to be a part of the data structure. A data structure may be chosen or created in computer science and computer programming to store data in order to be used with different methods. In some circumstances, the design of the data structure and the algorithm's fundamental operations are closely related. Each data structure comprises information about the data values, relationships between the data and — in some situations — functions that can be applied to the data.
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Answer:
The answer to this question is 1273885.3 ∅
Explanation:
<em>The first step is to determine the required hydraulic flow rate liquid if working pressure and if a cylinder with a piston diameter of 100 mm is available.</em>
<em>Given that,</em>
<em>The distance = 50mm</em>
<em>The time t =10 seconds</em>
<em>The force F = 10kN</em>
<em>The piston diameter is = 100mm</em>
<em>The pressure = F/A</em>
<em> 10 * 10^3/Δ/Δ </em>
<em> P = 1273885.3503 pa</em>
<em>Then</em>
<em>Power = work/time = Force * distance /time</em>
<em> = 10 * 1000 * 0.050/10</em>
<em>which is =50 watt</em>
<em>Power =∅ΔP</em>
<em>50 = 1273885.3 ∅</em>
Explanation:
750 microvolt is your answer
please mark as brilliant
