What is a construction worker with limited skills called?

What are the advantages of studying a scheduled course over a more freeform one?

anyanavicka [17]

Answer:

Taking responsibility for your own learning makes it easier to identify your strengths and weaknesses. Once these have been identified you can work on a learning plan that focuses on the areas that you need most help with, increasing the speed of your learning, and build the skills you have been trying to perfect.

Explanation:

8 0

3 years ago

Read 2 more answers

Ldentiy three industries that often need the skills of mechanical engineers. Briefly explain the skills that mechanical engineer

const2013 [10]

Answer:

3 industries that often need the skills of mechanical engineers are:

Automotive industry

Construction industry

Aerospace industry

The key skills mechanical engineers bring to these industries are effective technical skills, the ability to work under pressure, problem-solving skills, creativity and teamwork.

Explanation:

Automotive industry: The skills mechanical engineers bring to automotive industry include designing new cars for development, conducting laboratory testing for performance safety, and troubleshooting design or manufacturing issues with recalled vehicles. Automotive engineers have:

good mathematical skills, for instance in calculating the stresses power trains and other parts have to withstand;

understanding and application of principles of physics and chemistry to properly design engines, electrical systems and other car components;

good computer skills, because 21st century engineers rely on computer-assisted design software;

knowledge of ergonomics, which is applied in the process of designing a car so that the driver and passengers have a comfortable and functional environment, is another skill mechanical; engineers need.

Construction industry: Mechanical engineers are responsible for designing, building, establishing, and maintaining all kinds of mechanical machinery, tools, and components in the construction industry.

Aerospace industry: Mechanical engineers in aerospace industry produce specifications for design, development, manufacture and installing of new or modified mechanical components or systems. They design more fuel-efficient aircraft that cut emissions and build the fleets of satellites that power modern GPS technology.

4 0

3 years ago

Which of the following is NOT true about drawings and specifications?

hoa [83]

Answer:

sorry but we can't tell the answer because your not showing the drawings and specifications.

3 0

3 years ago

Assume that a person skiing high in the mountains at an altitude of h = 14200 ft takes in the same volume of air with each breat

goldfiish [28.3K]

Answer:

The ratio of the mass of oxygen inhaled for each breath at this high altitude compared to that at sea level is 64.7 %

Explanation:

Mass of air at sea level is given by;

$m_o = \rho_o V_o$

Mass of air at 14,200 ft altitude is given by;

$m_{14.2} = \rho _{14.2} V_{14.2}$

The ratio of the mass of oxygen at high altitude to that at sea level is given by;

$\frac{m_{14.2}}{m_o} = \frac{\rho _{14.2} V_{14.2}}{\rho _oV_{o}}\\\\ Assume \ that \ the \ air \ composition \ (V_{14.2} = V_o)\\\\\frac{m_{14.2}}{m_o} = \frac{\rho _{14.2} }{\rho _o}\\\\$

density of air at sea level, $\rho _o = 0.002378 \ slug/ft^3$

density of air at 10,000 ft = 0.001756 slug/ft³

density of air at 14,200 ft = x

density of air at 15,000 ft, = 0.001496 slug/ft³

Interpolate between 10,000 ft and 15,000 ft

$\frac{14,200 - 10,000}{15,000-10,000} = \frac{X - 0.001756}{0.001496 -0.001756}\\\\ 0.84(-0.00026) = X - 0.001756\\\\-0.0002184 = X - 0.001756\\\\X = 0.001756 - 0.0002184\\\\ X = 0.001538 \ slug/ft^3$

The ratio of the mass of oxygen at 14,200 ft to that at sea level is given by;

$\frac{m_{14.2}}{m_o} = \frac{\rho _{14.2}}{\rho_o} \\\\\frac{m_{14.2}}{m_o} =\frac{0.001538}{0.002378} = 0.647 = 64.7 \%$

Therefore, the ratio of the mass of oxygen inhaled for each breath at this high altitude compared to that at sea level is 64.7 %

6 0

3 years ago

Provide relevant parts of C-like codes for processes X1, X2, X3, X4 and X5 in the following synchronization problem. Each proces

labwork [276]

Answer:

import java.util.concurrent.Semaphore;

public class synchronization implements Runnable {

Semaphore b11 = new Semaphore(1);

@Override

//run method

public void run() {

boolean flvalue=false;

System.out.println("Started");

while(!flvalue) {

System.out.println("Thread is running");

}

System.out.println("Stopped");

}

//main method

public static void main(String args[]) {

final synchronization t11 = new synchronization();

Thread x1=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x2=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x3=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x4=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x5=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

x1.start();

x2.start();

x3.start();

x4.start();

x5.start();

}

private void mutualExclusion() {

try {

b11.acquire();

//mutual value

String tn=Thread.currentThread().getName();

String numberOy= tn.replaceAll("[^0-9]", "");

int num=Integer.parseInt(numberOy)+1;

System.out.println("Thread "+num + " is running");

Thread.sleep(100);

} catch (InterruptedException ie11) {

ie11.printStackTrace();

} finally {

b11.release();

String tn11=Thread.currentThread().getName();

String numberOy= tn11.replaceAll("[^0-9]", "");

int numval=Integer.parseInt(numberOy)+1;

System.out.println("Thread "+numval + " completed...!!!");

}

Explanation:

3 0

3 years ago