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1 year ago

The variation of the pressure of a fluid with density at constant temperature is known as the _____.

1 answer:

7 0

The variation of the pressure of a fluid with density at constant temperature is known as the coefficient of compressibility.

<h3>What is a compressor?</h3>

A compressor can be defined as a mechanical device that is designed and developed to provide power to refrigerators, air conditioners, and other heating or cooling mechanical devices (engines), especially by increasing the pressure on air or other applicable gases.

In an isothermal process, the coefficient of compressibility is also known as isothermal compressibility or compressibility and it refers to a measure of the variation of the pressure and relative volume of a fluid with density at constant temperature.

Read more on coefficient of compressibility here: brainly.com/question/25237713

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svetlana [45]

Answer:

Explanation:

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4 0

3 years ago

Read 2 more answers

A body of weight 300N is lying rough

kumpel [21]

Answer:

Horizontal force = 89.2 N

Explanation:

The frictional force = coefficient of friction * magnitude of the force (weight of the body) * cos theta

Substituting the given values, we get -

Frictional Force = 0.3*300 * cos 25 = 89.2 N

Horizontal force = 89.2 N

6 0

2 years ago

Match the words with their definitions

Pavlova-9 [17]

Wooden 2 X 8's, 10's, or 12's that run parallel to one another and support a floor or ceiling, and supported in turn by larger beams, girders, or bearing walls- Joist

Explanation:

Wooden 2 X 8's, 10's, or 12's that run parallel to one another and support a floor or ceiling, and supported in turn by larger beams, girders, or bearing walls- Joist
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5 0

2 years ago

The bar DA is rigid and is originally held in the horizontal position when the weight W is supported from C. The wires are made

Rom4ik [11]

Answer:

W = 112 lb

Explanation:

Given:

- δb = 0.025 in

- E = 29000 ksi (A-36)

- Area A_de = 0.002 in^2

Find:

Compute Weight W attached at C

Solution:

- Use proportion to determine δd:

δd/5 = δb/3

δd = (5/3) * 0.025

δd = 0.0417 in

- Compute εde i.e strain in DE:

εde = δd / Lde

εde = 0.0417 / 3*12

εde = 0.00116

- Compute stress in DE, σde:

σde = E*εde

σde = 29000*0.00116

σde = 33.56 ksi

- Compute the Force F_de:

F_de = σde *A_de

F_de = 33.56*0.002

F_de = 0.0672 kips

- Equilibrium conditions apply:

(M)_a = 0

3*W - 5*F_de = 0

W = (5/3)*F_de

W = (5/3)* 0.0672 = 112 lb

4 0

2 years ago

(a) The reverse-saturation current of a pn junction diode is IS = 10−11 A. Determine the diode voltage to produce currents of (i

kirill115 [55]

Answer:

The equation used to solve a diode is

$i_d = I_se^\frac{V_d}{V_T}-1$

$i_d$ is the current going through the diode
$I_s$ is your saturation current
$V_D$ is the voltage across your diode
$V_T$ is the voltage of the diode at a certain room temperature. by default, you always use $V_T=25.9mV$ for room temperature.

If you look at the equation, $i_d = I_se^\frac{V_d}{V_T}-1$ , you'd notice that the $e^\frac{V_d}{V_T}$ grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.