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2 years ago

The variation of the pressure of a fluid with density at constant temperature is known as the _____.

1 answer:

7 0

The variation of the pressure of a fluid with density at constant temperature is known as the coefficient of compressibility.

<h3>What is a compressor?</h3>

A compressor can be defined as a mechanical device that is designed and developed to provide power to refrigerators, air conditioners, and other heating or cooling mechanical devices (engines), especially by increasing the pressure on air or other applicable gases.

In an isothermal process, the coefficient of compressibility is also known as isothermal compressibility or compressibility and it refers to a measure of the variation of the pressure and relative volume of a fluid with density at constant temperature.

Read more on coefficient of compressibility here: brainly.com/question/25237713

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A piston–cylinder assembly contains 5 kg of air, initially at 2.0 bar, 30 C. The air undergoes a process to a state where the pr

Ainat [17]

Answer: wor done is 145. 06kJ

Heat transfer is 135.53kJ

Explanation:

No of moles of air = mass/molar mass = 5000g/28gmol^-1 = 172.65mol

P1 = 2bar =2*101300 =202600pa

T1 = 30° +273k = 303k

P2 =p1 = 202600pa

V2 =? T2 =?

Using pV = nRT

R = 8.314 PA m^3 mol^-1 k^-1

V1 = (172.65*8.314*303)/202600

V1 = 2.146m^3

For second state, 1.5pv = const = P1V1

V2 = (202600*2.146)/(1.5*202600)

V2 = 1.43m^3

Volume change = 2.146 - 1.43 =0.715m^3

Word done = pressure* volume change

W = 202600*0.716 = 145061.6J

= 145.061kJ

Using V1/T1 = V2/T2

T2 = V2T1/V1

=(1.43*303)/2.146 = 201.9k

For internal energy U

U = nCv*(T2 - T1)

*CV is the heat capacity at const. vol approximately 0.718J mol^-1 k^-1

U = 172.65*0.718*(201.9-303)

U = -12532.6J = -12.532kJ

The -ve means the system lost internal energy.

Q = U+W = total heat energy of system

Q = - 12.532+145.061 = 132.52 kJ

7 0

4 years ago

Pls pls pls pls plsss someone help pls

snow_tiger [21]

Answer:

I would like to help can you take a picture without the bot telling you something. Maybe then I can figure it out.

6 0

2 years ago

Someone claims that in fully developed turbulent flow in a tube, the shear stress is a maximum at the tube surface. Is this clai

Alika [10]

Answer:

Yes this claim is correct.

Explanation:

The shear stress at any point is proportional to the velocity gradient at any that point. Since the fluid that is in contact with the pipe wall shall have zero velocity due to no flow boundary condition and if we move small distance away from the wall the velocity will have a non zero value thus a maximum gradient will exist at the surface of the pipe hence correspondingly the shear stresses will also be maximum.

5 0

4 years ago

Compute the fundamental natural frequency of the transverse vibration of a uniform beam of rectanqular cross section, with one e

marshall27 [118]

Answer:

The natural angular frequency of the rod is 53.56 rad/sec

Explanation:

Since the beam is free at one end and fixed at the other hence the beam is a cantilevered beam as shown in the attached figure

We know that when a unit force is placed at the end of a cantilever the displacement of the free end is given by

$\Delta x=\frac{PL^3}{3EI}$