A population of size P increasing at the rate of 2% may be modelled as follows
P = P0<span> e</span>0.02 t<span> , where t is the number of years after t = 0 and P</span>0<span> is the population at t = 0. </span>
Let t = 0 corresponds to January 1, 2000 and therefore t = 4 corresponds to December 31. But P is 2,000,000 when t = 4. Hence
2,000,000 = P0<span> e</span>0.02*4
<span>Solve the above for P0</span>
P0<span> = 2,000,000 / e</span>0.02*4<span> = 1 846 000 (rounded to the nearest thousand) </span>
<span>P0 is the population at t = 0 or on January 1, 2000.
A. is the correct answer</span>
Given: x=48, y=13
Find: the value of the given expression.
Explanation:
Final answer: the required answer is 21.
Answer:
Step-by-step explanation:
16*
Answer:
-4√6-6√5
Step-by-step explanation:
-3√6-3√20-√6 = (-3√6-√6)-3√20 = -4√6-3√20
√20 = √4*√5 or 2√5
substitute that in and you get -4√6-3(2√5) which then becomes
-4√6-6√5
Answer:
You = bronze
Your brother = silver
Your sister = gold
Step-by-step explanation:
Your marks: 40/60
Your brother's marks: 46/60
Your sister's marks: 49/60
You can simplify the fractions, but you don't have to:
40/60 = 2/3
46/60 = 23/30
49/60 = 49/60
Now, divide each of the numerators by the denominators (turn the fraction into a decimal).
2/3 = 0.6667
23/30 = 0.7666667
49/60 = 0.8166667
(Note that these are all approximations as the real answers go on forever)
Lastly, multiply them all by 100 to get the percent.
0.6667 x 100 = 66.67% - bronze
0.76667 x 100 = 76.667% - silver
0.816667 x 100 = 81.6667% - gold
