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prisoha [69]
3 years ago
7

Y A chemist can purchase a 10% saline solution in 500 cubic centimeter containers, a 20% saline solution in 500 cubic centimeter

containers, and a 50% saline solution in 1,000 cubic centimeter containers. He needs 12,000 cubic centimeters of 30% saline solution. How many containers of each type of solution should he purchase in order to form this solution
Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0

Step-by-step explanation:

ultimately you need to end up with 30% solution

with 10%, 20%, and 50%, you are forced to tamper with the various percentages to reach the desired goal.

Since it is an even 12,000 (i.e. no 12500) and you have no hard container volumes to deal with, therefore find the easiest combination to reach 30%. In this case, (10%+50%)/2 = 30%

So therefore you need 12000 cubic centimeters of liquid, half of it being 50% and half being 10%.

12000/2 = 6000 cubic centimeters each

for 50%, each container is 1,000 cubic centimeters, so 6000/1000 =6 containers  for 10% each container is 500 cubic centimeters, so 6000/500 = 12 containers

Therefore, you need 6 containers of 50% solution and 12 containers of 10% solution.

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Suppose the null hypothesis, H0, is: Darrell has enough money in his bank account to purchase a new television. What is the Type
seropon [69]
<h2>Answer with explanation:</h2>

In statistics, The Type II error occurs when the null hypothesis is false, but fails to be rejected.

Given : Suppose the null hypothesis, H_0, is: Darrell has enough money in his bank account to purchase a new television.

Then , Type II error in this scenario will be when the null hypothesis is false, but fails to be rejected.

i.e. Darrell has not enough money in his bank account to purchase a new television but fails to be rejected.

3 0
3 years ago
For this item, a non-integer answer should be entered as a fraction using / as the fraction bar.
Kipish [7]

The numerical expression, 2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3 = <u>67/24</u> on simplification using the BODMAS rule.

In the question, we are asked to simplify the numerical expression:

2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3.

To simplify the expression, we will follow the BODMAS rule, where B means Brackets, O means Of, D means Divide, M means Multiplication, A means Addition, and S means Subtraction.

2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3

= 2/3 ÷ 16 + (3/4 + 1/6) ÷ 1/3 {Solving 2⁴ = 16, before proceeding BODMAS}.

= 2/3 ÷ 16 + ((9+2)/12) ÷ 1/3 {Solving Brackets by taking LCM}

= 2/3 ÷ 16 + 11/12 ÷ 1/3 {Simplifying}

= 2/3 * 1/16 + 11/12 * 3/1 {Solving divisions by taking reciprocals}

= 1/24 + 11/4 {Multiplying}

= (1 + 66)/24 {Adding using LCM}

= 67/24 {Simplifying}.

Thus, the numerical expression, 2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3 = <u>67/24</u> on simplification using the BODMAS rule.

Learn more about the simplification of numerical expression at

brainly.com/question/17205434

#SPJ1

The provided question is incomplete. The complete question is:

"Type the correct answer in the box. Use numerals instead of words. For this item, a non-integer answer should be entered as a fraction using / as the fraction bar.

Simplify the numerical expression.

2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3

The expression has a value equal to."

5 0
1 year ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

6 0
3 years ago
Why am this point be labeled with two names; 1 1/2 and 3/2
kakasveta [241]
3/2 is an improper fraction, where the denominator (bottom number) is smaller than the top (numerator)
1  1/2 is this same fraction but now it is not improper.  
5 0
2 years ago
3=J÷5 what does J equal
Iteru [2.4K]

Answer:

J = 15

Step-by-step explanation:

In order to find what the variable equals, you need to put it alone on one side of the equation. So to get rid of the 5, you have to do the opposite of division, which is multiplication. You multiply 5 and 3 to get 15. This will look like:

15 = J

Usually, there is something left to do on the number side, but in this case, there is nothing and you found your answer!

8 0
3 years ago
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