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Artist 52 [7]
3 years ago
7

identify the postulate of Dalton's theory that is violated by the following observations: 59.95% of one sample of titanium dioxi

de is titanium: 60.10 % of a different sample of titanium dioxide is titanium.
Chemistry
1 answer:
Inga [223]3 years ago
8 0

<u>Answer:</u> This violates the law of constant composition.

<u>Explanation:</u>

Dalton's theory is based on mainly two laws, which are law of conservation of mass and law of constant composition.

Law of constant composition states that a compound always contain the elements in the fixed ratio by their masses.

For Example: In water (H_2O), the hydrogen and oxygen are present in the fixed ratio of 1 : 9 by their mass.

We are given:

A sample of titanium dioxide having 59.95 % of titanium and another sample of titanium dioxide having 60.10 % of titanium.

As, the compound is titanium dioxide. So, the mass percent of titanium must remain the same in both the elements.

Hence, this violates the law of constant composition.

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Elements within the same group of the periodic table behave similarly because they have the same number of ?
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4 0
3 years ago
How many milliliters of C5H8 can be made from 366 mL C5H12 ?
zlopas [31]

The number of Ml  of C₅H₈  that can  be  made  from 366  ml  C₅H₁₂  is 314.7 ml  of C₅H₈


  <u><em>calculation</em></u>

 step  1: write  the  equation for  formation of C₅H₈

C₅H₁₂  →  C₅H₈  + 2 H₂

Step 2: find the mass of C₅H₁₂

mass = density × volume

= 0.620 g/ml × 366 ml =226.92 g

Step 3: find moles  Of  C₅H₁₂

moles  = mass÷  molar mass

from periodic table the  molar mass of  C₅H₁₂ = (12 x5) +(  1 x12) = 72 g/mol

moles = 226.92 g÷ 72 g/mol =3.152 moles

Step 4: use the  mole ratio  to determine the  moles of C₅H₈

C₅H₁₂:C₅H₈  is 1:1  from equation above

Therefore the  moles of C₅H₈  is also = 3.152  moles

Step 5: find the mass  of C₅H₈

mass = moles x molar mass

from periodic table the  molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol

= 3.152  moles x 68 g/mol = 214.34 g

Step 6: find Ml of  C₅H₈

=mass / density

= 214.34 g/0.681 g/ml = 314.7 ml



8 0
3 years ago
How much energy is needed to completely boil a 5.05g sample of water?
Keith_Richards [23]

Given what we know, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

<h3>Why does it take this much energy to boil the water?</h3>

We arrive at this number by taking into account the energy needed to boil 1g of water to its vaporization point. This results in the use of 2260 J of heat energy. We then take this number and multiply it by the total grams of water being heated, in this case, 5.05g, which gives us our answer of 11.4 kJ of energy required.

Therefore, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

To learn more about the behavior of water visit:

brainly.com/question/1416592?referrer=searchResults

8 0
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