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sukhopar [10]
3 years ago
13

Please help i will give brainliest!!! thank you =)

Chemistry
1 answer:
Anastasy [175]3 years ago
7 0

Answer:

Answer choice B. 2

Explanation:

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An experiment requires 0.52 M NH3(aq). The stockroom manager estimates that 15 L of the base is needed. What volume of 15 M NH3(
Bingel [31]

Answer: 0.52 L of 15 M NH_3(aq) will be used to prepare this amount of 0.52 M base.

Explanation:

But on diluting the number of moles remain same and thus we can use molarity equation.

C_1V_1(stock)=C_2V_2 (to be prepared)

where,

C_1 =concentration of stock solution = 15 M

V_1 = volume of stock solution = ?

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V_2 = volume of solution to be prepared = 15 L

15\times V_1=0.52\times 15

V_1=0.52L

Thus 0.52 L of 15 M NH_3(aq) will be used to prepare this amount of 0.52 M base

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3 years ago
How are organisms classified as Eukarya different from organisms classified as Archaea and Bacteria?
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Answer: D

Explanation: The Eukarya differ from the Archea and Bacteria in that their cells are eukaryotic, meaning they contain a membrane enclosed nucleus and other membrane enclosed organelles.

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a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3
aksik [14]

\huge\boxed{♔︎Answer♔︎}

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

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(a) The weight of sample after 3 hours

\textsf{ No. of half lives} =  \sf  \cancel\frac{3}{3}  = 1

The fraction of sample left

\sf  { \frac{1}{2} }^{1}  =  \frac{1}{2}

Mass of the sample left

\sf \frac{1}{2}  \times 120 =   \cancel\frac{120}{2}  = 60g

<u>6</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>3</u><u> </u><u>hours</u>

(b) The weight of sample after 6 hours

\textsf{ No. of half lives} =  \sf   \cancel\frac{6}{3}  = 2

The fraction of the sample left

\sf   { \frac{1}{2} }^{2}  =  \frac{1}{2}  \times  \frac{1}{2}  =  \frac{1}{4}

Mass of the sample left

\sf \frac{1}{4}  \times 120 =   \cancel\frac{120}{4}  = 30g

<u>3</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>6</u><u> </u><u>hours</u>

(c) The weight of sample after 9 hours

\textsf {No. of half lives} =  \sf   \cancel\frac{9}{3}  = 3

The fraction of sample left

\sf { \frac{1}{2} }^{3}  =  \frac{1}{2}  \times  \frac{1}{2}  \times  \frac{1}{2} =  \frac{1}{8}

Mass of sample left

\sf  \frac{1}{8}  \times 120 =  \cancel \frac{120}{8}  = 15g

<u>1</u><u>5</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>9</u><u> </u><u>hours</u><u>.</u>

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What is the frequency of radiation which has a wavelength of 7.00 x 10⁻⁵cm? In what region of the electromagnetic spectrum is th
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Answer:

5:59

Dot structures II: Multiple bonds (video)

Explanation:

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