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valentina_108 [34]
3 years ago
12

What is ionizing radiation, and why is it harmful? Give at least one example.

Physics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer:

Ionizing radiation is radiation, traveling as a particle or electromagnetic wave, that carries sufficient energy to detach electrons from atoms or molecules, thereby ionizing them. When the dose is high enough, ionizing radiation causes two types of harm to humans: direct tissue damage and cancer. Direct tissue damage happens when enough molecules are broken apart that the cells simply can no longer function. This can lead to radiation burns, radiation sickness, organ failure, etc.

Hope this helps!!

Have a nice evening :)

Explanation:

Ksenya-84 [330]3 years ago
8 0

Answer:

onizing radiation is a type of radiation that can break molecules into ions. These ions can disrupt the natural chemical reactions in the body and damage living cells. Examples of ionizing radiation include ultraviolet (UV) radiation in sunlight, X-rays used in medical imaging, and gamma rays produced by radioactive materials.

Explanation:

edge

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Why do mass numbers have a trailing decimal? use the following words describe for credit isotopes protons neutrons electrons in
Dmitry_Shevchenko [17]

Answer:a number without a decimal are generally not significant. Isotopes are atoms of same element which have the same atomic number but different number of neutrons. Isotopes of elements are represented in the following way: In an atom, the number of protons is equal to its atomic number.. An atom of an element is neutral in nature so atom contains the same number of protons and electrons.

Explanation:

3 0
3 years ago
A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.4
spin [16.1K]

By definition, the centripetal acceleration is given by:

a = \frac{v^2}{r}

Where,

v: tangential speed

r: radius of the circular path

Clearing the radio we have:

r = \frac{v^2}{a}

Substituting values we have:

r =\frac{0.51 ^ 2}{0.43}\\r = 0.6 m

Therefore, the radius of the circular path is equal to 0.60 meters.

Answer:

The radius of the circle is:

0.60 m

option1

8 0
2 years ago
Read 2 more answers
A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s
saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

F= \frac{mv^2}2

La energía gravitacional por,

F=\frac{GM_cm}{d}

Where m is the mass, v is the velocity, G the gravitational constant M_e the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

E= \frac{mv^2}2+\frac{GM_em}{d}

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2

The case of the comet is a closed orbit, so,

E<0

\frac{mv^2}2+\frac{GM_em}{d}

For parabolic orbit

E=0

\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2

For the sun and the earth

\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}

v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r

where R \approx 1AU

q^2d  For elliptical orbit

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3 years ago
What has to happen for a force to do work on an object?
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It has to move through a distance over time.
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3 years ago
The pressure in a container will stay the same if you ——?
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I think it’s D...not sure tho !
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