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zhuklara [117]
3 years ago
9

The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A:

Physics
2 answers:
FrozenT [24]3 years ago
6 0

the answer is point c

vichka [17]3 years ago
5 0

Answer:

The kinetic energy will be maximum at point C.

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Each of the rods depicted below were machined from same stock metal. They were originally machined to be the same length, but th
Shkiper50 [21]

The force required to extend a rod increases as the cross sectional area

increases.

The rod that experiences the largest force is <u>rod B</u>

Reason:

The elongation of a rod by the application of a force is given by the

following formula;

\Delta L = \dfrac{F \cdot L}{A \cdot E}

From the above equation, we have that the elongation is inversely

proportional to the cross sectional area, such that the extension of a rod by

a given force reduces as the cross sectional area of the rod increases.

Therefore, the force required to extend the length of a rod by a specific

amount increases as the cross sectional area of the rod increases,

indicating that the rod with the largest cross sectional area require the

most force and therefore, experiences the largest force.

The rod that experiences the largest force is the rod with the largest cross

sectional area, which is <u>rod B</u>

Learn more here:

brainly.com/question/12937199

4 0
2 years ago
The acceleration of an object would increase if there was an increase in:
kolezko [41]

Answer:

Its either B or A

Explanation:

6 0
2 years ago
A uniform sphere (I = 2/5 MR 2 ) rolls down an incline. (a) What must be the incline angle if the linear acceleration of the cen
Liono4ka [1.6K]

Answer:

Part a)

\theta = 8.05 degree

Part b)

a = 1.37 m/s^2

Explanation:

As the uniform sphere is rolling down the inclined plane then the net force on the sphere is given as

mg sin\theta - F_f = ma

also we have torque equation on it

F_f R = I\alpha

for pure rolling

a = R \alpha

F_f = \frac{Ia}{R^2}

now we have

mg sin\theta = ma + \frac{Ia}{R^2}

now we have

mg sin\theta = (m + \frac{2}{5}m)a

a = \frac{5}{7}g sin\theta

now given that

a = 0.10 g

so we have

0.10 g = \frac{5}{7} g sin\theta

sin\theta = 0.14

\theta = 8.05 degree

Part b)

If the inclined plane is frictionless then the acceleration is given as

a = g sin\theta

a = 9.8(0.14)

a = 1.37 m/s^2

5 0
3 years ago
Read 2 more answers
Which of the following is a unit of acceleration?
olasank [31]

{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}

\longrightarrow The rate of change of velocity per unit time is called acceleration.

\longrightarrow Its SI unit is m/s².

\huge\boxed{\fcolorbox{blue}{red}{Thank you}}

7 0
2 years ago
How far does a wave travel in three cycles?
eduard
It will be 3 wavelengths because 1 cycle = 1 wavelength. 
6 0
3 years ago
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