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3 years ago

Look at photo then awser!

Mathematics

2 answers:

KatRina [158]3 years ago

8 0

Answer:

It crosses the y-axis at 9, so a point would be

(0,9)

Gala2k [10]3 years ago

4 0

(0, 9)

An ordered pair is an (x,y) so you can use any point that falls on the line.

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Please answer this I need help asap

Yanka [14]

Answer:

(12, 48 )

Step-by-step explanation:

Given the 2 equations

y = 5x - 12 → (1)

y = 3x + 12 → (2)

Substitute y = 5x - 12 into (2)

5x - 12 = 3x + 12 ( subtract 3x from both sides )

2x - 12 = 12 ( add 12 to both sides )

2x = 24 ( divide both sides by 2 )

x = 12

Substitute x = 12 into either of the 2 equations and evaluate for y

Substituting into (2)

y = 3(12) + 12 = 36 + 12 = 48

solution is (12, 48 )

8 0

3 years ago

If sin just answer the please lol i don't feel like typing<br><br> ASAP

yaroslaw [1]

Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

Quadrant 1: Both positive.

Quadrant 2: Sine positive, cosine negative.

Quadrant 3: Both negative.

Quadrant 4: Sine negative, cosine positive.

Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

#SPJ1

5 0

1 year ago

I need help with this question

vlabodo [156]

K= 52!!

hoped this helped .

3 0

3 years ago

Which ordered pair is a solution of the system of a linear equation below? Y= 1/4x +2 y= x-1

Tanya [424]

Answer: x = 4, y = 3

<u>Step-by-step explanation:</u>

$y=\dfrac{1}{4}x+2$ and $y=x-1$

Using substitution method we get:

$x-1=\dfrac{1}{4}x+2\\\\\text{subtract}\ \dfrac{1}{4}x\ \text{from both sides}\rightarrow \dfrac{3}{4}x-1=2\\\\\text{add 1 to both sides}\rightarrow \dfrac{3}{4}x=3\\\\\text{multiply both sides by 4}\rightarrow 3x=12\\\\\text{divide both sides by 3}\rightarrow x=4\\\\\text{Insert x = 4 into one of the original equations to solve for y:}\\y=x-1\\y =(4)-1\\y=3$