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larisa86 [58]
3 years ago
6

A spring with spring constant 17.0 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest.

It is then pulled down 4.00 cm and released. The ball makes 35.0 oscillations in 18.0 seconds.
1) What is its the mass of the ball?
Express your answer using two significant figures.
m = _____ g

2) What is its maximum speed?
Express your answer using two significant figures.

= _____ cm/s
Physics
1 answer:
Sonbull [250]3 years ago
6 0

Explanation:

Given that,

Spring constant of the spring, k = 17 N/m

It is then pulled down 4.00 cm and released, A = 4 cm = 0.04 m

The ball makes 35.0 oscillations in 18.0 seconds.

The time required to complete one oscillation is :

T=\dfrac{18}{35}=0.514\ s

Angular velocity,

\omega=\dfrac{2\pi }{T}\\\\\omega=\dfrac{2\pi }{0.514}\\\\\omega=12.22\ rad/s

(1) The relation between spring constant, angular velocity and mass is given by :

\omega^2=\dfrac{k}{m}\\\\m=\dfrac{k}{\omega^2}\\\\m=\dfrac{17}{(12.22)^2}\\\\m=0.11\ kg

(2) The maximum speed is given by :

v=A\omega\\\\v=0.04\times 12.22\\\\v=0.49\ m/s            

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Ax = 4.3 m
Dimas [21]

Answer:

the answer will be option no b plss mark me brainliest

7 0
3 years ago
18. How does magnetic force affect the energy in a system of magnets when the magnets are released and begin to move? a The magn
astra-53 [7]

When the magnets are released and begin to move, the magnetic force changes potential energy into kinetic energy;<u> option D</u>

<h3>What is magnetic force?</h3>

Magnetic force can be defined as the force of attraction or repulsion that is felt or produced between the magnetic poles and electrically charged moving particles.

Magnetic force is the force that exists due to the attractio or repulsion of objects place around the region of space where a maget exerts its force.

When a magnet is released ai a system of magnets and allowed to move it increases the kinetic eergy of the system by converting potential energy to kinetic energy.

Learn more about magnetic force at: brainly.com/question/28989998

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5 0
1 year ago
Positive Charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positiv
deff fn [24]

Answer:

 electric field E = - k Q (1 /r(r-a)), force    F = - k Q qo / r (r-a) and force for r>>a    F ≈ - k Q qo / r²

Explanation:

You are asked to find the electric field of a continuous charge distribution, so we must use the equation

       

           E = k ∫dp /r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C², r is the distance between the load distribution and the test charge, in this case everything is on the X axis.

We must find the charge differential (dq), let's use that uniformly distributed and create a linear charge density

          λ = q / x

As it is constant, we can write it based on differentials

         λ = dq / dx

         dq = λ dx

We already have all the terms, let's  integrate enter its limits, lower the distance from the left end of the distribution to the test charge (x = r) and the upper limit that is the distance from the left end of distribution to the test load ( x = r - a) where r> a

         E = k ∫ λ dx / x²

         E = k la (- 1 / x)

Let's get the negative sign from the parentheses

         E = - k λ (1 / x)

         E = - k λ (1 /(r-a)  -1 /r) = - k λ [a / r (r-a)]

Let's change the charge density with the value of the total charge λ = Q / a

         E = - k Q/a  [a / r (r-a)]

         E = - k Q (1 /r(r-a))

b) We calculate the force.  

         F = E qo

         F = - k Q qo / r (r-a)

c) the force for charge porbe very far r >> a. In this case we can take r from the parentheses and neglect (a/r)

         F = - k Qqo / r² (1 -  a/r)

         F ≈ - k Q qo / r²

6 0
3 years ago
A tin atom has 50 electrons. Electrons in the ________ subshell experience the lowest effective nuclear charge.
Alexus [3.1K]

Answer:

5p

Explanation:

We are given that a tin has 50 electrons.

We have to find in which subshell electrons experience the lowest effective nuclear charge.

We know that the electron in outermost shell experience the lowest effective nuclear charge.

Electronic configuration is given by

50=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^2

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.

Answer: 5p

5 0
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Sonbull [250]
The answer was is C.53 kg
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