A spring with spring constant 17.0 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest.
1 answer:
Explanation:
Given that,
Spring constant of the spring, k = 17 N/m
It is then pulled down 4.00 cm and released, A = 4 cm = 0.04 m
The ball makes 35.0 oscillations in 18.0 seconds.
The time required to complete one oscillation is :
Angular velocity,
(1) The relation between spring constant, angular velocity and mass is given by :
(2) The maximum speed is given by :
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Answer:
Explanation:
Work is the product of force and distance.
We know that 96 Joules of work were done and a 16 Newton force was applied to the object.
- W= 96 J
- F= 16 N
Substitute the values into the formula.
First, let's convert the units. This will make cancelling units easier later in the problem. 1 Joule (J) is equal to 1 Newton meter (N*m), so the work of 96 Joules equals 96 Newton meters.
Now, solve for distance by isolating the variable, d. It is being multiplied by 16 Newtons and the inverse of multiplication is division. Divide both sides of the equation by 16 N.
The units of Newtons cancel.
The object moved a distance of <u>6 meters.</u>
Answer:
24.084 m/s
Explanation:
From the law of conservation of linear momentum
Total momentum before collision equals to the total momentum after collision
Since momentum=mv where m is mass and v is velocity
where
is the mass of the truck,
is velocity of the truck,
is the common velocity of moving and standing truck after collision and
is the mass of the standing truck
Making the subject we obtain
Substituting as 25000 Kg,
as 22.3 m/s,
as 2000 Kg we obtain
Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive
The truck was moving at 24.084 m/s