3 years ago

PLEASE HELP! ASAP!

Physics

1 answer:

Mice21 [21]3 years ago

5 0

Answer:

1.) Radio

2.) Star

Explanation:

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Answer:

Its answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

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Which law of motion accounts for the following statement? "A ball hit by a man travels faster than one hit by a boy."

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a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's fi

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Answer:

the final velocity of the wagon is 6 m/s.

Explanation:

Given;

initial velocity of the wagon, u = 4 m/s

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The final velocity of the wagon is calculated as;

E = ¹/₂m(v² - u²)

$m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 = \frac{2E}{m} + u^2\\\\v = \sqrt{\frac{2E}{m} + u^2} \\\\v = \sqrt{\frac{2(350)}{35} + (4)^2}\\\\v = 6 \ m/s$

Therefore, the final velocity of the wagon is 6 m/s.

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3 years ago

An archer shoots an arrow 75 m distant target; the bull's-eye of the target is at the same height as the release height of the a

Liono4ka [1.6K]

Answer:

$16.25^{\circ}$

Explanation:

R = Horizontal range of projectile = 75 m

v = Velocity of projectile = 37 m/s

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Horizontal range is given by

$R=\dfrac{v^2\sin2\theta}{g}\\\Rightarrow \theta=\dfrac{\sin^{-1}\dfrac{Rg}{v^2}}{2}\\\Rightarrow \theta=\dfrac{\sin^{-1}\dfrac{75\times 9.81}{37^2}}{2}\\\Rightarrow \theta=16.25^{\circ}$

The angle at which the arrow is to be released is $16.25^{\circ}$ .

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