Answer:
The required volume of water the student needs is 4.9 litres of water
Explanation:
From the diagram related to the question, we have;
The dimensions of the tank are;
Length of tank = 24.0 cm = 0.24 m
Width of tank = 21.0 cm = 0.21 m
Depth of tank = 13.0 cm. = 0.13 m
Allowance provided between the top of the tank and the top of the water = 2.0 cm
Diameter of the round bottom flask, D = 10.5 cm = 0.105 m
Therefore, the radius of the round bottom flask, r = 0.105/2 = 0.0525 m
Therefore we have;
Depth of water in the tank = Depth of tank - Allowance provided between the top of the tank and the top of the water
∴ Depth of water in the tank = 13.0 - 2.0 = 11.0 cm = 0.11 m
Given that the flask is immersed in the water contained in the tank to raise the tank water level, we have;
Volume of water + Volume of flask in the tank = Length of tank × Width of tank × Depth of water in the tank
Volume of water + Volume of flask in the tank = 0.24 × 0.21 × 0.11 = 0.005544 m³ = 0.005544 m³× 1000 l/m³ = 5.544 l
The volume of the spherical flask = 4/3·π·r³ = 4/3·π·0.0525³ = 6.06×10⁻⁴ m³ = 6.06×10⁻⁴ m³ × 1000 l/m³ = 0.606 l
The required volume of water the student needs , V = Volume of water + Volume of flask in the tank - The volume of the spherical flask = 5.544 l - 0.606 l = 4.9 l.
