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3 years ago

What are different kinds of electromagnetic radiation?

Chemistry

2 answers:

MA_775_DIABLO [31]3 years ago

4 0

Radio waves, Micro waves, infrared, visible light, ultra violet, x-rays, and Gamma rays.

dem82 [27]3 years ago

3 0

Gamma rays, x rays, infrared, ultra violet, visible light, radio waves, mricro waves

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How many molecules are in the following formula?<br> 2(NH4)3PO4

poizon [28]

Answer:15 I think

Explanation:

7 0

3 years ago

If an automobile air bag has a volume of 11.7 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact

Usimov [2.4K]

Answer:

33.95 grams of NaN3

Explanation:

Number of moles of NaN3 = mass (m)/MW = m/65 mole

I mole of NaN3 requires 22.4L air bag

m/65 mole of NaN3 required 11.7L

22.4m/65 = 11.7

22.4m = 65×11.7

22.4m = 760.5

m = 760.5/22.4 = 33.95grams of NaN3

5 0

3 years ago

Define an arrhenius base and describe properties of bases. use an example to explain how an arrhenius base will behave in water.

bulgar [2K]

The species which gives OH⁻ ion is known as Arrhenius base.

<h3>What are Arrhenius bases?</h3>

Arrhenius bases are those species which are giving hydroxide ion (OH⁻) in an aqueous solution.

Properties of Arrhenius bases are:

They are bitter in taste.
Converts red litmus paper to blue color.
Have pH value in the range of 7.1 to 14.

Examples of Arrhenius bases are sodium hydroxide (NaOH), potassium hydroxide (KOH), etc.

Hence, Arrhenius bases gives OH⁻ in an aqueous solution and NaOH is an example of this.

To know more about Arrhenius bases, visit the below link:

brainly.com/question/1049247

#SPJ1

5 0

2 years ago

Which of the following elements has the highest electronegativity?

zvonat [6]

The answer of this question is Oxygen

8 0

3 years ago

Read 2 more answers

A 10.000g ice cube is added to 100.000g of water at 80.0 oC in a calorimeter. The final temperature of the water in the calorime

Ket [755]

<u>Answer:</u> The amount of heat needed to melt the ice cube is 6.083 kJ

<u>Explanation:</u>

The processes involved in the given problem are:

$1.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\2.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(65.5^oC,338.5K)$

<u>For process 1:</u>

To calculate the amount of heat required to melt the ice at its melting point, we use the equation:

$q_1=m\times \Delta H_{fusion}$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of ice = 10.000 g

$\Delta H_{fusion}$ = enthalpy change for fusion = 334.16 J/g

Putting all the values in above equation, we get:

$q_1=10.000g\times 334.16J/g=3341.6J$

<u>For process 2:</u>

To calculate the heat required at different temperature, we use the equation:

$q_2=mc\Delta T$

where,

$q_2$ = heat absorbed

m = mass of ice = 10.000 g

c = specific heat capacity of water = 4.184 J/g.°C

$\Delta T$ = change in temperature = $T_2-T_1=[65.0-0]^oC=65.5^oC$

Putting values in above equation, we get:

$q_2=10.000g\times 4.184J/g.^oC\times 65.5^oC\\\\q_2=2741.83J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[3341.6+2741.83]J=6083.43J=6.083kJ$

Hence, the amount of heat needed to melt the ice cube is 6.083 kJ

4 0

3 years ago