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kupik [55]
2 years ago
5

Evelyn bean, 52 years of age, is admitted to the same-day surgery unit for an elective laparoscopic cholecystectomy. the patient

presents with jaundice of the skin and sclera. the patient's urine is dark and the patient stated that she has clay-colored stools. he stated she has occasional colicky pain in her right upper quadrant of her abdomen radiating to her back. the patient had pre admission testing 1 week ago and the results are on the patient's chart. the record of patient education and an informed written consent are also on the chart. (learning objective 2 and 3)
a. what additional procedure will be performed if the common bile duct is obstructed by a gallstone
Biology
1 answer:
jeka942 years ago
6 0
The patient can be subjected to intraoperative cholangiography wherein a stent in the bile duct will be placed and a radiopaque dye will be injected. X-rays will be taken. This is to locate the level of obstruction and to confirm if there is a common bile duct obstruction. In extracting stones, the surgeon can prefer doing an endoscopic retrograde cholangiopancreatography or ERCP and perform basket extraction of the common bile duct stone; or to surgically remove the sphincter of Oddi to allow easy passage of the stones.
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Write the difference between single celled organisms and multi-cells organisms below.
VLD [36.1K]

Answer: Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism, while multicellular organisms use many different cells to function.

4 0
3 years ago
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Alu element at the PV92 locus on Chromosome 16. In this population, 436 people have a heterozygous genotype and 102 people have
Lesechka [4]

Answer:

Explanation:

According to the exercise we can infer that for the Alu insert:

p: positive allelic frequency

q: negative allelic frequency

maintaining that the population is in equilibrium we can carry out the following formula

p + q = 1 and pp + 2pq + qq = 1

looking for the genotype frequency we clear and obtain the following data

genotype frequency of 2pq = 436/1000 = 0.436

The genotype frequency of qq = 102/1000 = 0.102

This is how we look now:

number of positive people for Alu = 1000- (436 + 102) = 1000- 538 = 46

In this way it is resolved that:

genotypic frequency of pp = 462/1000 = 0.462

  p = 0.462 + (0.436 / 2) = 0.462 + 0.218 = 0.680

q = 0.102+ (0.436 / 2) = 0.102 + 0.218 = 0.320

According to the exercise carried out it is deduced:

The value of p in the population is = 0.68

We conclude that our prognosis showing a homozygous positive genotype is: 0.462

6 0
2 years ago
True or false?, an Environment containing no calcium is the best for Brian shrimp egg hatching provide evidence in the form of o
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False, an environment containing no calcium is not the best for Brian shrimp egg hatching. The following evidence statements can be used to support our answer.

  1. Control shows 9 hatchlings after 72 hours whereas the treatment of 10mg/100ml concentration of calcium shows 17 hatchlings.
  2. Control shows 9 hatchlings after 72 hours whereas the treatment of 20mg/100ml concentration of calcium shows 28 hatchlings.
  3. Control shows 9 hatchlings after 72 hours whereas the treatment of 10mg/100ml concentration of calcium shows 39 hatchlings.
7 0
3 years ago
This is an observable trait of an organism that can mask the recessive trait.
Naily [24]
This law states an organism has two different alleles for a trait and the allele that is expressed in the phenotype, masking the expression of the other allele,is said to be dominant. The allele whose expression is masked is said to be recessive.
7 0
3 years ago
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16. The method of movement that requires the expenditure of ATP molecules is
stira [4]

Answer:

It is active transport

Explanation:

because the ions are moving against the concentration gradient

3 0
2 years ago
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