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solong [7]
3 years ago
14

A radio wave has a frequency of 8.6 × 108 hz. what is the energy of one photon of this radiation (h = 6.63 × 10–34 j • s)?

Physics
1 answer:
My name is Ann [436]3 years ago
5 0

Answer: 57.018\times10^{-26}J

Energy is directly proportional to the frequency.

The energy of a photon is given by:

E=h\nu

Where, E is the energy and \nu is the frequency.

Frequency of the radio wave is given:

\nu=8.6\times10^8 Hz

h=6.63\times10^{-34}J.s

Multiply the above two:

Energy,

E=h\nu=6.63\times10^{-34}J.s\times8.6\times10^8 Hz= 57.018\times10^{-26}J

Hence, the energy of each photon of radio wave having frequency  \nu=8.6\times10^8 Hz is 57.018\times10^{-26}J

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The statement is true.

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Answer:

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

W = 810.6 J

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Using first law of thermodynamics:

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W = Work Done = PΔV =

P = Pressure = 2 atm = 202650 Pa

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Q = ΔU + PΔV

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ΔU = 500 J - 810.6 J

<u>ΔU = - 310.6 J (negative sign indicates decrease in internal energy)</u>

<u></u>

b.

The work done can be simply calculated as:

W = PΔV

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Answer:

Q = 5267J

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M = mass of substance =508g

Q = (508g) * (0.377 J/g·°C) * (27.5C)

Q= 5266.69J

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