V = u + at
0 = u -9.8 x 5.5
u = 9.8 x 5.5 = 53.9 m/s
Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial (
) and final speeds (
), measured in meters per second, of the aircraft and likewise the runway length (
), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (
), measured in meters per square second:
If we know that 
, 
and 
, then the acceleration that the jet must have is:
The acceleration that the jet liner that must have is 2.241 meters per square second.
<span>-- the product of the net charges on the objects;. -- the distance between the centers of their net charges. (Pretty much identical to the formula for gravitational force)</span>
A=F/m
a=(3000000)/(20000)
a=15 m/s^2
Answer: 1160 m
Explanation:
Speed = distance / time. Plug in 40 m/s for speed and 29 s for time in order to get the distance, 1160 m.
