Answer:
90 C
Explanation:
Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,
I = dQ/dt
dQ = Idt
∫dQ = ∫Idt
Q = It................................ Equation 1
Where Q = amount of charge, I = current, t = time.
Given: I = 3.6 A, t = 25 s.
Substituting into equation 1,
Q = 3.6(25)
Q = 90 C.
Hence the amount of charge passing through the cross section of the conductor = 90 C
I believe the answer is potential difference
Practically yes
So
If mass is more output may come less so it affects the efficiency practically
But thepritically it doesn't
Answer:
The resistance is 0.124 ohm.
Explanation:
It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.
diameter, d = 2.05 mm
radius, r = 1.025 mm
Length, L = 24 m
resistivity of copper = 1.7 x 10^-8 ohm m
Let the resistance is R.
Since there is no diagram I can see to prove my answer, I must infer that a heat source should be applied to the solid substance and cause the atoms in the solid to spread further apart and become a different state, in which atoms will be able to freely move, gas.
