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saw5 [17]
2 years ago
11

Define heat capacity of a substance.Write the S.I unit of heat capacity.​

Physics
1 answer:
creativ13 [48]2 years ago
6 0

Define heat capacity of a substance:

  • The heat capacity of a substance can be defined as the amount of heat required to change its temperature by one degree.

Write the S.I unit of heat capacity:

  • Joule per Kelvin

\:  \:  \:

  • Joule per Celsius

\:  \:  \:

\:  \:  \:

\:  \:  \:

\:  \:  \:

\:  \:  \:

\:  \:  \:

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-,-

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Explanation:

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2 years ago
Ethanethiol (; also called ethyl mercaptan) is commonly added to natural gas to provide the ""rotten egg"" smell of a gas leak.
Tju [1.3M]

Answer:

S = 27500J / 308.15molK

Explanation:

Entropy measures the degree of disorganization of a system. It is measured in the entropy change that is equal to the heat exchanged divided by the temperature at which the process occurs.

S2-S1 = Q / T

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S = 27500J / 308.15molK

3 0
3 years ago
An automobile is sitting on a hill which is 20 m higher than ground level. Find the mass of the automobile if it contains 362,60
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M= ?
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6 0
3 years ago
A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a
Elza [17]

Answer:

\dfrac{dz}{dt}=0.65\ ft/s

Explanation:

Given that

x= 150 ft

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y= 14 ft

From the diagram

z^2=x^2+y^2

When ,x= 150 ft and y= 14 ft

z^2=150^2+14^2

z=\sqrt{150^2+15^2}

z=150.74 ft

z^2=x^2+y^2

By differentiating with respect to time t

2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}

z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}

Here x is constant that is why

\dfrac{dx}{dt}=0

z\dfrac{dz}{dt}= y\dfrac{dy}{dt}

Now by putting the values in the above equation we get

150.74\times \dfrac{dz}{dt}=14\times 7

\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s

\dfrac{dz}{dt}=0.65\ ft/s

Therefore the distance between balloon and observer increasing with 0.65 ft/s.

5 0
3 years ago
What is the unique geological feature found on Mercury surface?
Cloud [144]

Answer:

The surface of Mercury has landforms that indicate its crust may have contracted. They are long, sinuous cliffs called lobate scarps. These scarps appear to be the surface expression of thrust faults, where the crust is broken along an inclined plane and pushed upward.

Explanation:

I hope this helps a little bit.

3 0
3 years ago
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