PE = mgh
so (75kg)(9.8m/s2)(100m) = 73,500 Joules
KE = 1/2 m * v^2
so (1/2)(75kg)(60m/s)^2 = 135,000 Joules
ME = 208,500 Joules
Explanation:
From a new Moon, when the Moon is situated in orbit between the Earth and the Sun with its dark side in shadow facing towards us, the amount of lunar surface visible from the Earth increases through waxing crescent, first quarter and waxing gibbous phases until it becomes full.
Or
The new moon is the phase that is invisible to us here on Earth because the moon is between the earth and the sun, and its illuminated side is facing away from us. A solar eclipse occurs when the moon moves in front of the sun, blocking it from our view on Earth.
I believe its B ,<span> (the direction the north end of a </span>compass<span> needle points, corresponding to the direction of the Earth's </span>magnetic<span> field lines)</span>
Answer:
The force required is equal to
.
Explanation:
We know that
Torque = force × perpendicular distance
= F × R = I×
I = M×
From above equation
.............. 1
We know that
...........................2
Given that t= 2 sec


From equation 1 and 2 , we get
F =
= 
Upon substituting the above values we will be getting
F = 
Answer:
The average force the golf club exerts on the ball is 600 N
Explanation:
Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced
F = m× (v₂ - v₁)/(Δt)
The given parameters of the motion of the ball are;
The mass of the ball, m = 45 g = 0.045 kg
The initial velocity of the ball, v₁ = 0 m/s
The speed with which the ball was hit by the golfer, v₂ = 40 m/s
The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)
By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;
F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N
The average force the golf club exerts on the ball = F = 600 N.