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yanalaym [24]
2 years ago
11

Light from the sun travels in electromagnetic waves. Which of these statements describe electromagnetic waves?

Physics
1 answer:
kupik [55]2 years ago
7 0

Complete Question:

Light from the sun travels in electromagnetic waves. Which of these statements describe electromagnetic waves? Choose the 3 that apply.

Group of answer choices.

a) consist of transverse wave patterns.

b) can move through a vacuum.

c) caused by a vibration in a medium.

d) consist of longitudinal wave patterns.

e) requires a medium, such as air, to travel.

f) made of vibrating electric and magnetic fields.

Answer:

a) consist of transverse wave patterns

b) can move through a vacuum

f) made of vibrating electric and magnetic fields

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is light and radio waves. Light from the sun travels in electromagnetic waves.

The statements which describe electromagnetic waves are;

I. It consist of transverse wave patterns.

II. It can move through a vacuum.

III. It is made of vibrating electric and magnetic fields.

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Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

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Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

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3 years ago
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Explanation:

Given

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F =(kq1q2) / r²

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Answer:

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