When the air density is 0 kg/m°(vacuum), how long will it take an object to reach terminal velocity?
1 answer:
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The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.
- The Universe was 5 percent its current size when light left objects now at redshift of <u>19</u>.
Reasons:
The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;
Where;
a₀ = The current size of the Universe
a = The size of the early Universe = 5% of a
Therefore;
0.05 + 0.05·z = 1
- The redshift is of the observed light is, z = <u>19</u>
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Answer:
Explanation:
The gravitational force between the proton and the electron is given by
where
G is the gravitational constant
is the proton mass
is the electron mass
r = 3 m is the distance between the proton and the electron
Substituting numbers into the equation,
The electrical force between the proton and the electron is given by
where
k is the Coulomb constant
is the elementary charge (charge of the proton and of the electron)
r = 3 m is the distance between the proton and the electron
Substituting numbers into the equation,
So, the ratio of the electrical force to the gravitational force is
So, we see that the electrical force is much larger than the gravitational force.