Answer:
True or False
Explanation:
Because.....
easy 50% chance you are right
 
        
             
        
        
        
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25. 
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the 
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity =  1.35 mm
λ =  wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1 
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
brainly.com/question/15413360
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From the Hooke's law , the extension force of an elastic material is directly proportional to the extension. 
That is, F = k e, where F is the force , k is the constant and e is the extension
 F = 10 × 10 = 100 N
e = 1mm or 0.001 m
Hence, k = F/e
                = 100 N/ 0.001
                = 100000 N/m or 100 N/mm
        
             
        
        
        
I think transfers is the answer