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kap26 [50]
3 years ago
12

Which of the following points lie in the solution set to the following system of inequalities?

Mathematics
2 answers:
Vitek1552 [10]3 years ago
4 0

Answer:

Step-by-step explanation:

y ≤ x − 5

1<10-5

1<5

Pair: (10,1)

y ≤ −x − 4

-10<-1-5

-10<-6

Pair: (1,-10)

nikdorinn [45]3 years ago
3 0

Answer:

<h2>(1, −10)</h2>

Step-by-step explanation:

If we graph this system of inequalities, we could find the solution.

From the graph you can deduct that the only right answer is the last one (1,-10), because the area of solution is only for negative values of <em>y.</em>

Therefore, the right choice is the last one.

If you can't graph, you can try another method. If we replace the value in the system, it should satisfy it, that is, it should gives us a true result like 0<1 for example. Let's try

For x=1 and y=-10, we have

-10 ≤ 1 − 5

-10 ≤ −1 − 4

-10 ≤ -4

-10 ≤ -5

As you can see, the result is true, because -10 is less than -4 and -5, so that's the right answer.

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I'm not 100% sure if I'm doing it the right way, but I think the answer is the factorial of the number of letters divided by the factorials of the number of elements of each kind of element (in this case, the same letters)


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= 63 · 120


= 7,560 permutations

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The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

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b = -k and

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3 years ago
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