Answer:
(a): It spends on the trip 2.75 hr (2 hours 45 minutes)
(b): The person travels 213.9 km.
Explanation:
Vp= 77.8 km/h
V1= 89.5 km/h
V2= 0 km/h
t2= 0.36hr
t1= ?
Vp= (V1*t1 + V2*t2) / (t1 + t2)
clearing t1:
t1= 2.39 hr
Trip time= t1+t2
Trip time= 2.75 hr (a)
Distance traveled= V1*t1
Distace traveled= 213.9 km (b)
Y - yo = Vo*t - g * (t^2) / 2
Vo = - 9.0 m/s
t = 0.50 s
=> y - yo = -9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s)^2 / 2 = - 4.5m - 1.225m = - 5.725 m.
Answer: option c) - 5.7
Answer:
The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Explanation:
Given the data in the question;
Using the Clapeyron equation


where
is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu
T is the temperature ( 15 + 460 )R
m is the mass of water ( 0.5 Ibm )
is specific volume ( 1.5 ft³ )
we substitute
/
272.98 Ibf-ft²/R
Now,

where P₁ is the initial pressure ( 50 psia )
P₂ is the final pressure ( 60 psia )
T₁ is the initial temperature ( 15 + 460 )R
T₂ is the final temperature = ?
we substitute;


480.275 R
Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R