Answer:
3727.24km/h
Explanation:
Hello!
To solve this problem we must first know what is the distance from the earth to the moon, this will be our radius.
=384400Km
Then we find the distance traveled which would be the perimeter of a circle = 2πr, finally to find the speed we divide the distance traveled by 27 days.
Finally we use conversion factor to have the speed in km / h
solving

the moon is orbiting at speed of 3727.24km/h
The magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
The magnitude of the force on a charged particle moving in a magnetic field is given by the formula,
F= qvB
Here q is the charge on proton = 1.6 x 10^-19 C.
v is the velocity with which the particle is moving = 6.00 x 10^6 m/s
And B is the value of the magnetic field = 1.5 T
Putting the given values in the above equation,
F = 1.6 x 10^-19 x 6 x 10^6 x 1.5 = 1.44 x 10^-12 N.
Hence, the magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
To know more about "magnetic force", refer to the link given below:
brainly.com/question/13791875?referrer=searchResults
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Answer:
The angular displacement of the blade is 576,871.2 radians
Explanation:
Given;
angular speed of the Helicopters rotor blades, ω = 510 rpm (revolution per minute)
time of motion, t = 3 hours
The angular speed of the Helicopters rotor blades in radian per second is given as;

The angular displacement in radian is given as;
θ = ωt
where;
t is time in seconds
θ = (53.414)(3 x 60 x 60)\\
θ = 576,871.2 radians
Therefore, the angular displacement of the blade is 576,871.2 radians
10,000 units of momentum.
p=mv
20,000=m(2v)
10,000=mv