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SOVA2 [1]
3 years ago
5

Which of the following is not a characteristic of electromagnetic waves? (A) They can travel at various speeds through any one m

aterial. (B) the can be refracted. (C) They can be reflected. (D) They can travel through a vacuum.
Physics
2 answers:
MaRussiya [10]3 years ago
6 0
B. C, and D are true. A isn't.

In any given material, EM waves have a single speed. It's

(the speed of light in vacuum)
divided by
(the index of refraction of that material).
Eva8 [605]3 years ago
3 0

The answer would be A. Have a nice day.

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Difference between upthrust force and normal reaction force.
irakobra [83]

Answer:

Explanation:

Both are contact forces arising at the interface between two bodies. In the fluid this interface might be irregular, and it completely surrounds a submerged object. For a solid it is usually a single flat surface - but it can be a collection of surfaces, which do not need to be flat or regular, and which can surround the object

Upthrust occurs at a fluid-solid interface whereas normal reaction occurs at a solid-solid surface. However, it is possible to generate the same fluid-like phenomenon of upthrust by immersing a solid object in sand or small beads and agitating them to simulate the pressure of atoms. With 

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2 years ago
Find the radius using the centripetal acceleration formula: acceleration = 6.6 x 10^6 m/s^2 velocity = 2,000 rev/s
aksik [14]

the radius is 231

Explanation:

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3 years ago
What is work?(theoretically)
emmasim [6.3K]

Answer:

force×distance

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4 0
3 years ago
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar
kakasveta [241]

Answer:

W=4037.36\ J

Explanation:

Given:

mass of ice melted, m=3.3\times10^{-2}\ kg

time taken by the ice to melt, t=5\ min=300\ s

latent heat of the ice, L=3.34\times 10^5\ J

Now the heat rejected by the Carnot engine:

Q_R=m.L

Q_R=0.033\times 3.34\times 10^5

Q_R=11022\ J

Since we have boiling water as hot reservoir so:

T_H=373\ K

The cold reservoir is ice, so:

T_L=273\ K

Now the efficiency:

\eta=1-\frac{T_L}{T_H}

\eta=1-\frac{273}{373}

\eta=26.81\%

Now form the law of energy conservation:

Heat supplied:

Q_S-W=Q_R

where:

Q_S= heat supplied to the engine

Q_S-\eta\times Q_S=Q_R

Q_S(1-\eta)=Q_R

Q_S=\frac{11022}{1-0.2681}

Q_S=15059.36\ J

Now the work done:

W=Q_S-Q_R

W=15059.36-11022

W=4037.36\ J

8 0
2 years ago
A simple pendulum takes 128s to complete 40 oscillations what is the time period of the pendulum
Serhud [2]

Explanation:

Parameters

Number of oscillation = 40 oscillations

Time of oscillation = 128s

Formular

Period (T) = <u>No of oscillation</u>

Time taken

T = <u>128</u>

40

T=3.2s

3 0
3 years ago
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