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Elena-2011 [213]

3 years ago

8

A 0.500 kg rock is whirled in a vertical circle of a radius 0.60 m . the velocity of the rock at the bottom of the swing is 4.0

m/s . what is the acceleration
A 3.3 m/s^2
B 26.6 m/s^2
C 13.3 m/s^2
D 6.6 m/s^2

1 answer:

OLEGan [10]3 years ago

7 0

Explanation:

Centripetal acceleration is:

a = v² / r

a = (4.0 m/s)² / 0.60 m

a = 26.6 m/s²

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Answer:

hence initial wavelength is $\lambda =4.86\times10^{-12}m$

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