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3 years ago

What is a likely consequence of preventing prescribed burns to forest ecosystems?

1 answer:

5 0

The forest ecosystem will regain back its natural ecology compared to burning of the forest and other illegal activities done to the forest. And also, some of the animals living in that forest will live and those that are endangered will not be threatened.

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Lauren rode the bus home from the mall on Saturday. She felt the bus accelerate as it left the parking lot, and then the bus tur

Alex_Xolod [135]

A. is the one it did not say

7 0

3 years ago

A group of students are provided with three objects all of the same mass and radius. The objects include a solid cylinder, a thi

SOVA2 [1]

Answer:

Sphere, cylinder hoop

Explanation:

To analyze Which student is right it is best to propose the solution of the problem. Let's look for the speed of the center of mass. Let's use the concept of mechanical energy

In the highest part of the ramp

Em₀ = U = mg y

In the lowest part

Here the energy has part of translation and part of rotation

$E_{mf}$ = $K_{T}$ + $K_{R}$

$E_{mf}$ = ½ m $v_{cm}$ ² + ½ I w²

Where I is the moment of inertia of the body and w the angular velocity that relates to the velocity of the center of mass

$v_{cm}$ = w r

w = $v_{cm}$ / r

Let's replace

$E_{mf}$ = ½ I ( $v_{cm}$ / r)²

Energy is conserved

mg y = ½ m $v_{cm}$ ² + ½ I $v_{cm}$ ² / r2

½ (m + I / r²) $v_{cm}$ ² = m g y

½ (1 + I / m r²) $v_{cm}$ ² = g y

$v_{cm}$ = √ [2gy / (1 + I / mr²)]

This is the velocity of the center of mass of the bodies, as they all have the same radius with comparing this point is sufficient. Now let's use the speed definition

v = d / t

t = d / v

t = d / (√ [2gy / (1 + I / mr²)])

t = (d / √ 2gy) √(1 + I / m r²)

Therefore we see that time is proportional to the square root. All quantities are constant and the one that varies is the moment of inertia.

The moments of inertia of

Sphere is Is = 2/5 M r²

Cylinder Ic = ½ M r²

Hoop Ih = M r²

Let's replace each one and calculate the time

Sphere

ts = (d / √2gy) √ (1 + 2/5 Mr² / mr²)

ts = (d / √ 2gy) √ (1 +2/5) = (d / √ 2gy) √(1.4)

ts = (d / √ 2gy) 1.1

Cylinder

tc = (d / √2gy) √ (1 + 1/2 Mr² / Mr²)

tc = (d / √2gy) √ (1 + ½) = (d / √ 2gy) √ 1.5

tc = (d / √ 2gy) 1.2

Hoop

th = (d / √2gy) √ (1 + mr² / mr²)

th = (d / √2gy) √(1 + 1) = (d / √ 2gy) √ 2

th = (d / √ 2gy) 1.41

We have the results for the time the body that arrives the fastest is the sphere and the one that is the most hoop. Therefore the correct answer is

ts < tc < th

Sphere, cylinder hoop

5 0

3 years ago

The drawing shows two long, thin wires that carry currents in the positive z direction. Both wires are parallel to the z axis. T

erica [24]

Answer:

The magnitude of the magnetic field at the origin is $2.56\times 10^{-6}\ T$ .

Explanation:

Given :

50-A wire is in the x-z plane and is 5 m from the z axis.

Also , 40-A wire is in the y-z plane and is 4 m from the z axis.

Now , since both the wire are perpendicular to each other .

Therefore , magnetic field are also perpendicular to each other .

Magnetic field at origin due to wire 1 is :

$B_1=\dfrac{\mu_oI_1}{2\pi R_1}\\\\B_1=\dfrac{(50)\mu_o}{2\pi( 5)}\\\\B_1=\dfrac{5\mu_o}{\pi}$

Magnetic field at origin due to wire 2 is :

$B_2=\dfrac{\mu_oI_2}{2\pi R_2}\\\\B_2=\dfrac{(40)\mu_o}{2\pi( 4)}\\\\B_2=\dfrac{4\mu_o}{\pi}$

Now , therefore net magnetic field is :

$B=\sqrt{B_1^2+B_2^2}\\\\B=\sqrt{(\dfrac{5\mu_o}{\pi})^2+(\dfrac{4\mu_o}{\pi})^2}\\\\B=\dfrac{\sqrt{41}\mu_o}{\pi}$

Putting value of $\mu_o=4\pi \times 10^{-7}\ H/m$

We get ,

$B=\sqrt{41}\times 4\times 10^{-7}\\B=2.56\times 10^{-6}\ T$

Therefore, the magnitude of the magnetic field at the origin is $2.56\times 10^{-6}\ T$ .

5 0

3 years ago

Suppose a log's mass is 5kg. After burning, the mass of the ash is 1 kg. Explain what could have happened to the other 4kg.

snow_lady [41]

Mass never just disappears. The other 4kg had to go somewhere. It could have left the scene of the fire in the form of smoke particles and hot gases.

3 0

4 years ago

Why the earth is not in thermal equilibrium with the sun?

mr_godi [17]

Changes in the earths ability to reflect sunlight (called the 'albeido') due to clouds and other weather like ice formations set up feedback loops that prevent a perfect equlibrium with the sun.

4 0

4 years ago