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marishachu [46]
3 years ago
9

K-Mart is offering a 15% discount on children's clothing. Susan sees a jumper she likes for $30. How much does she pay for the j

umper?​
Mathematics
1 answer:
shtirl [24]3 years ago
7 0

The answer is $25.5!

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Which two points satisfy y=-x2(^)+2x+4 and x+y=4?
Wewaii [24]
Use subtitution method to solve the problem.

First, change y to the value of x in order to find the exact value of x.
x + y = 4
y = 4 - x

Second, subtitute y with 4 - x from the first equation
y = -x² + 2x + 4
4 - x = -x² + 2x + 4
move all terms to the left side
x² - 2x - x + 4 - 4 = 0
x² - 3x = 0
x(x - 3) = 0
x = 0 or x = 3

Third, now we have 2 values of x. Find the value of y for each of x
For x = 0
y = 4 - x
y = 4 - 0
y = 4

For x = 3
y = 4 - x
y = 4 - 3
y = 1

The solution is (0,4) and (3,1). The answer is option b
5 0
3 years ago
I will give brainliest to the correct answers! yep that's YOU
siniylev [52]

Answer: Yes, because the amount of money you save for every beverage bought is constant, and if you buy 0 beverages, you’ll save $0. That means it the situation is graphed, the line produced will be linear and crosses through the origin, which are the requirements for a proportional relationship.

3 0
2 years ago
team has a 75% chance to win each of the 3 games they will play this week. Clare simulates the week of games by putting 4 pieces
kaheart [24]

Answer: 88

Step-by-step explanation:

check google if its wrong :)

6 0
3 years ago
Complete the inequality 17/20 ___ 88%
Margarita [4]

Answer:

17/20 < 88%

Step-by-step explanation:

17/20 = .85

.85 < .88

17/20 < 88%


5 0
3 years ago
Read 2 more answers
Sin2A+Sin2B÷Sin2A-Sin2B=Tan(A+B)÷Tan(A-B) Prove that​
igor_vitrenko [27]

Take L.H.S sin2A+sin2B/sin2A-sin2B

= sin2A+sin2B/sin2A-sin2B

Put

[sinC+sinD = 2sin(C+D)/2cos(C-D)/2]

[sinC-sinD = 2cos(C+D)/2.sin(C-D)/2]

= 2 sin(2A+2B)/2 cos(2A-2B)/2 / 2 cos(2A+2B) sin(2A-2B)

= sin(A+B).cos(A-B)/cos(A+B).sin(A-B)

= sin(A+B)/cos(A+B) . cos(A-B)/sin(A-B)

= tan(A+B).cot(A-B)

= tan(A+B).1/tan(A-B)

= tan(A+B)/tan(A-B)

∴ Hence we proved sin2A+sin2B/sin2A-sin2B=tan(A+B)/tan(A-B)

8 0
2 years ago
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