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Anton [14]
3 years ago
5

Help me to solve it . It’s urgent

Physics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer: 0°

Explanation:

Step 1: Squaring the given equation and simplifying it

Let θ be the angle between a and b.

Given: a+b=c

Squaring on both sides:

... (a+b) . (a+b) = c.c

> |a|² + |b|² + 2(a.b) = |c|²

> |a|² + |b|² + 2|a| |b| cos 0 = |c|²

a.b = |a| |b| cos 0]

We are also given;

|a+|b| = |c|

Squaring above equation

> |a|² + |b|² + 2|a| |b| = |c|²

Step 2: Comparing the equations:

Comparing eq( insert: small n)(1) and (2)

We get, cos 0 = 1

> 0 = 0°

Final answer: 0°

[Reminders: every letters in here has an arrow above on it]

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Alona [7]

Here light ray strikes to interface at an angle of 45 degree and then refracts into other medium such that it will bend towards boundary.

So here the angle of incidence will be less than the angle of refraction as light moves towards the boundary after refraction which mean it will bend away from the normal

here it can be said that medium 2 will be rarer then medium 1

So here the possible options are

1. Water  

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2. Diamond  

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So in above two options medium 1 is denser and medium 2 is rarer

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3 years ago
Which of the following terms is given to a pair of stars that appear to change position in the sky, indicating that they are orb
Ad libitum [116K]

Answer:

option A

Explanation:

The correct answer is option A

The binary star system is the system in which two stars are continuously orbiting each other,

In the eclipsing binary system, two stars revolve about there center of mass and in this system one one-star eclipse another star.

Spectroscopic binary stars are found from the observation of radial velocity and the brighter member of such binary can be seen to have continuously changed the wavelength and periodic velocity.

When the pairs of stars appear to change position in the sky then it is known as visual binary.

5 0
3 years ago
The special theory of relativity deals with space and time under what special condition?
sergij07 [2.7K]
<h2>Answer: Invariance of the speed of light in vacuum  </h2>

Special relativity was proposed on 1905 by Einstein, who developed his theory based on the following two postulates:  

<em>1. The laws of physics are the same in all inertial systems. There is no preferential system.  </em>

<em>2. The speed of light in vacuum has the same value for all inertial systems.  </em>

<em></em>

Focusing on the first postulate, it can be affirmed that any measurement on a body is made with reference to the system in which it is being measured.

 

In addition, it deals with the <u>dilation of time</u> stating that <u>time passes at different rates in regions of different gravitational potential</u>. That is, the greater the local distortion of space-time due to gravity, the slower the time passes.  

On the other hand, following what relativity establishes, bodies within a gravitational field follow a curved space path.  

7 0
3 years ago
Cold plasma used in TVs is different from the solar plasma because ___________.
Arisa [49]

Answer: B i believe

Explanation:

5 0
4 years ago
A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. How much energy is lost? Group of answer choices 0.5
bogdanovich [222]

Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J

Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.

<h3>What is gravitational potential energy?</h3>
  • The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.
  • The gravitational potential energy of a body at a height h with respect to the height h will be,

                                          U=mgh

  • Expression for gravitational potential energy loss will be,

                                        E=U_i-U_f

<h3>How to solve the problem?</h3>
  • The total energy before the ball dropped will be,

                 U_i=mgh_i=60*10^-3kg*9.8m/s^2*2m=1.176 J

  • The total energy after when the ball rebounds to 1.5m will be,

                 U_f=mgh_f=60*10^-3kg*9.8m/s^2*1.5m=0.882J

  • The total energy loss will be,

                E=1.176-0.882=0.294J

Thus, we can conclude that, the energy loss will be,0.294J.

Learn more about the gravitational potential energy here:

brainly.com/question/28044692

#SPJ4

3 0
2 years ago
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