Hello!
<em>a) What is the change in momentum</em>?
The change of the momentum is the velocity, because the velocity is reduced to zero.
We can calculate the aceleration, applicating the formula:
![\boxed{a=\frac{V-Vi}{t} }](https://tex.z-dn.net/?f=%5Cboxed%7Ba%3D%5Cfrac%7BV-Vi%7D%7Bt%7D%20%7D)
Like you see, the final velocity will be zero, so:
![a = \dfrac{0m/s-40m/s}{4s}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B0m%2Fs-40m%2Fs%7D%7B4s%7D)
![a = \dfrac{-40m/s}{4s}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B-40m%2Fs%7D%7B4s%7D)
![a = -10\ m/s^{2}](https://tex.z-dn.net/?f=a%20%3D%20-10%5C%20m%2Fs%5E%7B2%7D)
Like you see, the aceleration applicate by superman is of <u>-10 m/s^2.</u>
If the aceleration is negattive, means the velocity will decrease.
<em>b.) What is the magnitud of the force wich superman exerts on the train?</em>
For calculate the force applicate for superman, lets applicate the second law of Newton:
![\boxed{F=ma}](https://tex.z-dn.net/?f=%5Cboxed%7BF%3Dma%7D)
Lets replace and resolve it:
F = 8x10^3 kg * (-10 m/s^2)
F = 8000 kg * (-10 m/s^2)
F = -80 000 N
The force applicated is of <u>-80000 Newtons.</u>
When the force is negative means the force applicated in the another direction of the object what is traveling.