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Feliz [49]
3 years ago
7

PLEASE PLEASE HELP (Picture)

Physics
1 answer:
atroni [7]3 years ago
7 0

Answer:

light slows it down

Explanation:

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A what is a negatively charged Atoms
mr Goodwill [35]

Answer:

Negatively charged or positively charged atom is generally termed as ANION/CATION. Short Explanation: If an atom loses electrons or gains protons, it will have a net positive charge and is called a Cation. If an atom gains electrons or loses protons, it will have a net negative charge and is called an Anion.

Explanation:

7 0
3 years ago
A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material
Llana [10]

Answer:

a) C = 40.138\,pF, b) q = 16.056\,nC, c) U = 3.212\,\mu J

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

C = K\cdot \epsilon_{o}\cdot \frac{A}{d}

Where:

K - Dielectric constant.

\epsilon_{o} - Vaccum permitivity.

A - Plate area.

d - Distance between plates.

Hence, the capacitance of the system is:

C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)

C = 4.014\cdot 10^{-11}\,F

C = 40.138\,pF

b) The charge can be found by using the definition of capacitance:

q = C\cdot V_{batt}

q = (4.014\times 10^{-11}\,F)\cdot (400\,V)

q = 1.606\times 10^{-8}\,C

q = 16.056\,nC

c) The energy stored in the charged capacitor is:

U=\frac{1}{2}\cdot Q\cdot V_{batt}

U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)

U = 3.212\times 10^{-6}\,J

U = 3.212\,\mu J

3 0
2 years ago
Read 2 more answers
A light bulb converts electrical energy into light energy and also some thermal energy. The amount of electrical energy is 50 Jo
Kitty [74]
If the amount of electrical energy is 50 Joules before the conversions, then it would be 50 Joules after the conversion.

According to law of conservation of energy, we cannot create or destroy energy so it remains constant

Hope this helps!
8 0
3 years ago
The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. Given that Earth’s mass is 5.97 × 1024 kg and its radius i
Sergio039 [100]
<span>We can use an equation to find the gravitational force exerted on the HST. F = GMm / r^2 G is the gravitational constant M is the mass of the Earth m is the mass of the HST r is the distance to the center of the Earth This force F provides the centripetal force for the HST to move in a circle. The equation we use for circular motion is: F = mv^2 / r m is the mass of the HST v is the tangential speed r is the distance to the center of the Earth Now we can equate these two equations to find v. mv^2 / r = GMm / r^2 v^2 = GM / r v = sqrt{GM / r } v = sqrt{(6.67 x 10^{-11})(5.97 x 10^{24}) / 6,949,000 m} v = 7570 m/s which is equal to 7.570 km/s HST's tangential speed is 7570 m/s or 7.570 km/s</span>
6 0
3 years ago
Read 2 more answers
2. A certain object revolves at a rate of 30 rpm. Please determine the frequency and period of this
schepotkina [342]

Answer:

The time period of the motion is, T = 0.03 s

The frequency of the rotation is, f = 30 Hz

Explanation:

Given data,

The rotational speed of an object, ω = 30 rpm

                                                          ω = 188.5 rad/s

The time period of motion is,

                            T = 2π / ω

Substituting the given values in the above equation

                               = 2π / 188.5

                            T = 0.03 s

The time period of the motion is, T = 0.03 s

The frequency of rotation,

                                f = 1 /T

                                   = 1 / 0.03

                                   = 30 Hz

Hence, the frequency of the rotation is, f = 30 Hz

7 0
3 years ago
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