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Karolina [17]
2 years ago
11

A “K-9 cannon” uses a powerful rubber band to launch a tennis ball(mass of 0.0577 kg) vertically upwards. The tennis ball has a

velocity of 25.0 m/s as it leaves the barrel.
A. How long is the tennis ball in the air?
Physics
1 answer:
dezoksy [38]2 years ago
7 0

Answer:

t = 5.1[s]

Explanation:

To solve this problem we must first use the following equation of kinematics.

v_{f}=v_{o} -g*t

where:

Vf = final velocity = 0

Vo = initial velocity = 25 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

Now replacing:

0 = 25-9.81*t\\t=25/9.81\\t=2.54[s]

Note: The key to understand this problem is that when the tennis ball is in the highest position its velocity is zero.

So it will take the same time from the highest point to the ground

t = 2.54 +2.54

t = 5.09 [s]

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6 0
3 years ago
how much energy would microraptor gui have to expend to fly with a speed of 10 m/sm/s for 1.0 minute?
Ray Of Light [21]

Much energy as would Microraptor gui have to expend to fly with a speed of 10 m/s for 1.0 minutes is 486 J.

The first step is to find the energy that Microraptor must release to fly at 10 m/s for 1.0 minutes. The energy that Microraptor must expend to fly can be found using the relationship between Power and Energy.

P = E/t

Where:

P = power (W)

T = time (s)

Now, a minimum of 8.1 W is required to fly at 10 m/s. So, the energy expended in 1 minute (60 seconds) is

P = E/t

E = P x t

E = 8.1 x 60

E = 486 Joules

Thus, the energy that Microraptor must expend to fly at 10 m/s for 1.0 minutes is the 486 J.

Learn more about Microraptor gui here brainly.com/question/1200755

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3 0
11 months ago
The different shapes of the moon seen from Earth are called
Anastaziya [24]

Answer:

phases of moon

Explanation:

.................

3 0
2 years ago
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The angular velocity of a flywheel obeys the equa tion w(1) A Br2, where t is in seconds and A and B are con stants having numer
makkiz [27]

Answer:

A \to rad/s

B  \to rad/s^3

Explanation:

\omega_z(t)=A + Bt^2

Required

The units of A and B

From the question, we understand that:

\omega_z(t) \to rad/s

This implies that each of A and Bt^2 will have the same unit as \omega_z(t)

So, we have:

A \to rad/s

Bt^2 \to rad/s

The unit of t is (s); So, the expression becomes

B * s^2 \to rad/s

Divide both sides by s^2

B  \to \frac{rad/s}{s^2}

B  \to rad/s^3

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2 years ago
Sharp claws in wild animals is an example of which type of adaptation?
Sati [7]

Answer:

Structural adaptation

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When any physical body part of an organism helps it in surviving, then this mechanism of survival is called a structural adaptation. For example short tail of penguins helps them in balancing on their heels and tails due to which they are able to reduce heat released from their feet. Thus, any physical parts of an organism that helps them in coping with the surrounding physical environment /predators are refereed to as a mode of structural adaptation.

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