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3 years ago

A scalar quantity has

1 answer:

3 0

A scalar quantity is described by a magnitude only. It includes speed, time, mass, and volume. There is no direction involved. Therefore, your answer is C- Magnitude but no direction.

I hope I've helped! :)

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What is the cell theory?

Kisachek [45]

Cell theory is a scientific theory which describes the properties of cells. These cells are the basic unit of structure in all organisms and also the basic unit of reproduction.

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3 years ago

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Arysha enjoys playing lacrosse on the school team. Suppose Arysha throws a lacrosse ball with a force of 6 N, and the resulting

olasank [31]

Answer:

$Mass = 0.14kg$

Explanation:

Given

$Force = 6N$

$Acceleration = 43m/s^2$

Required

Determine the mass of the ball

This question will be answered using Newton's second law of motion.

Which states that

$Force = Mass * Acceleration$

Substitute values for Force and Acceleration

$6N = Mass * 43m/s^2$

Make Mass the subject

$Mass = \frac{6N}{43m/s^2}$

$Mass = 0.13953488372$

$Mass = 0.14kg$ --- (approximated)

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3 years ago

Please Answer the question in the picture ASAP PLEASE

attashe74 [19]

Answer:

HERE IS YOUR ANSWER

Explanation:

PLEASE MARK MY ANSWER AS BRAINLIEST IF THE ANSWERS ARE CORRECT .

Beacuse of the loose connection of the wire .

Straight

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3 years ago

"Two electrons in an atom are separated by 1.4 × 10−10 m, the typical size of an atom. What is the force between them? The Coulo

Rudiy27

Answer:

$F\approx 1.17551\times 10^{-8} N$

Explanation:

In order to find the force between the two electrons, we need to use Coulomb's law. In its scalar form, the law is given by:

$F=k_c \frac{q_1*q_2}{r^2}$

Where:

$k_c=Coulomb\hspace{3}constant\approx 9\times10^{9} \frac{Nm^2}{C^2} \\q_1\hspace{3}and\hspace{3}q_2=Magnitudes\hspace{3}of\hspace{3}the\hspace{3}charges\\r=Distance\hspace{3}between\hspace{3}the\hspace{3}charges$

The electric charge of an electron is a known constant given by:

$q_e \approx -1.6 \times 10^{-19} C$

So:

$q_1=q_2=q_e \approx -1.6 \times 10^{-19} C$

Therefore, replacing the data provided in the Coulomb's law equation:

$F=(9\times 10^{9})\frac{(-1.6\times 10^{-19})*(-1.6\times 10^{-19})}{(1.4\times 10^{-10})^2} =1.175510204\times10^{-8} \approx 1.17551\times10^{-8}N$

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3 years ago

Difference betwwen Acclerat<br>ion and retradation

BartSMP [9]

I’m pretty sure one increases just straight up velocity and the other is kind of a deceleration

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3 years ago